从联合所有查询中计算重复项

Question

尝试从联合所有查询中计算重复项。如果我添加一个组，它会消除重复项。我需要计算两个帐户中的两个重复项，但该帐户中可能有我不关心的重复项。因此独特的

Select CRID.CId as CIds FROM
(
    Select Distinct([CId]) as CId From [dbo].[MyTable] Where AccountId = 'E7888A78-043F-4C34-BB72-1EDC97D32EDB'
    UNION ALL
    Select Distinct([CId]) as CId From [dbo].[MyTable] Where AccountId = 'CC94E667-7776-4427-A6D9-6492C5CDA617'
) CRID
Having Count(CRID.CId > 1) -- Can't use having

Answer 1

因为你只有两张桌子，你可以这样做：

select count(*) - count(distinct cid) as num_duplicates
from ((Select Distinct([CId]) as CId 
       from [dbo].[MyTable]
       Where AccountId = 'E7888A78-043F-4C34-BB72-1EDC97D32EDB'
      ) union all
      (Select Distinct([CId]) as CId
       from [dbo].[MyTable]
       Where AccountId = 'CC94E667-7776-4427-A6D9-6492C5CDA617'
      )
     ) CRID;

但是，您似乎想要同时具有AccountIds 的Cids。我只会去：

select cid
from dbo.MyTable
where AccountId in ('E7888A78-043F-4C34-BB72-1EDC97D32EDB', 'CC94E667-7776-4427-A6D9-6492C5CDA617')
group by cid
having count(distinct AccountId) > 1;

如果您想要计数，请使用子查询：

select count(*)
from (select cid
      from dbo.MyTable
      where AccountId in ('E7888A78-043F-4C34-BB72-1EDC97D32EDB', 'CC94E667-7776-4427-A6D9-6492C5CDA617')
      group by cid
      having count(distinct AccountId) > 1
     ) t;