microsoft access下的sql查询语句

Question

我有 2 张桌子：

Employee:
    ID
    SalaryPerDay
    overTimeHoursPrice
    .....
    .....

Schedule:
    ID
    EmployeeID
    Date
    Attending  (boolean)
    loan
    discount
    overTimeHours

多对一关系

我想要一个查询返回

[员工姓名]和

[总和（贷款）] 和

[总和（折扣）] 和

[sum(overTimeHours)] 和

[count(attending)] 其中参加 = true 和

[count(attending) * SalaryPerDay] 和

[sum(overTimeHours)* overTimeHoursPrice ] 和

[(count(attending) * SalaryPerDay) + (sum(overTimeHours)* overTimeHoursPrice) - (sum(discount)) - (sum(loan))]

1- 其中 Date >= [date1] 和 Date

2- 其中 Date >= [date1] And Date

（date1 和 date2 和 name 是参数）

Answer 1

这样的事情应该可以解决问题....

SELECT 
  emp.EmployeeName, sum_loan, sum_discount, sum_overTimeHours, count_attending, 
  (count_attending*SalaryPerDay) as totalDayPay,
  (sum_overTimeHours*overTimeHoursPrice) as totalOverTimePay,
  ((count_attending*SalaryPerDay) + (sum_overTimeHours*overTimeHoursPrice) -
    sum_discount - sum_loan) as grandTotal
FROM Employee emp
  INNER JOIN (SELECT
      EmployeeID,
      sum(loan) as sum_loan,
      sum(discount) as sum_discount,
      sum(overTimeHours) as sum_overTimeHours,
      sum(iif(Attending,1,0)) as count_attending
    FROM Schedule
    WHERE Date >= {date1} and Date <= {date2}
    GROUP BY EmployeeID
  ) sch
  ON emp.ID = sch.EmployeeID
WHERE emp.EmployeeName = {name}

注意两个WHERE 子句。您可以根据需要调整这些以实现您的两种不同的参数化限制。

编辑#1：
由于存储在Schedule.Attending 字段中的“布尔”的实际数值存在一些不确定性，我已经调整了上面的查询以明确说明布尔值。为此，我使用了特定于 MSAccess 的表达式函数 IIF()。这是一个比仅仅假设该字段包含1 或0 更强大的解决方案。

编辑#2： 我还应该注意，语法会根据您使用它的位置而略有不同。以上是派生表的“标准 sql”语法（即INNER JOIN 关键字后面括号内的子查询）。如果您通过 ODBC 连接运行此查询，则上述语法有效。

但是，如果您尝试在 Access 本身中创建查询，则需要在子查询周围使用带有结尾句点 [ ]. 的方括号，而不是括号 ( )。所以而不是：

SELECT ... FROM Employee emp INNER JOIN (SELECT ... ) sch ON ...

使用这个：

SELECT ... FROM Employee emp INNER JOIN [SELECT ... ]. sch ON ...

Answer 2

我想你想要：

SELECT e.EmployeeName, 
   Sum(s.loan) AS SumOfloan, 
   Sum(s.discount) AS SumOfdiscount, 
   Sum(s.overTimeHours) AS SumOfoverTimeHours, 
   Sum(Abs([Attending])) AS Attnd, 
   Sum([SalaryPerDay]*Abs([Attending])) AS SalyAttnd, 
   Sum([overTimeHoursPrice]*[overtimehours]) AS OTCost, 
   Sum(([SalaryPerDay]*Abs([Attending])+[overTimeHoursPrice]*[overtimehours])-([loan]-[discount])) AS Due
FROM Employee e
INNER JOIN Schedule s ON e.ID = s.EmployeeID
WHERE s.Date Between [date1] And [Date2]
AND EmployeeName = [Name] 
GROUP BY e.ID, e.EmployeeName

请注意，布尔值是 0 或 -1，因此 [SalaryPerDay]*Abs([Attending] = Salary * 1，如果参加或 0，如果不参加。