SQL语法错误，同时使用java（eclipse）答案

【问题标题】：SQL syntax error, while using java(eclipse)SQL语法错误，同时使用java（eclipse）
【发布时间】：2014-05-08 09:33:35
【问题描述】：

我正在使用 java eclipse 以及 mySQL 工作台来相互连接。现在我正在使用 java 来编写一些查询，但是在查询问题中遇到了一个我不熟悉的错误的特定问题，并且我在进行了几个可以正常工作的 sql 查询后第一次遇到。任何帮助表示赞赏。我将列出代码，然后跟进错误。

public static void stopTimes() throws SQLException
    {
    stmt = conn.createStatement();
    System.out.println("Enter Route Number: ");
    String route = scan.nextLine();
    System.out.println("Direction?");
    String dir = scan.nextLine();
    System.out.println("Enter the first stop number:");
    String stop1 = scan.nextLine();
    System.out.println("Enter the second stop number:");
String stop2 = scan.nextLine();      
String sql;

  sql = "SELECT DISTINCT bus_stops.stopID, street1, street2 FROM bus_stops INNER JOIN scheduled_stops ON bus_stops.stopID = scheduled_stops.stopID"+
              "WHERE scheduled_stops.routeNumber = '"+route+"' "+
              "AND scheduled_stops.direction = '"+dir+"' "+
              "AND scheduled_stops.stopTime > (SELECT stopTime FROM scheduled_stops WHERE scheduled_stops.stopID = '"+stop1+"' ORDER BY scheduled_stops.stopTime asc limit 1)"+ 
              "AND scheduled_stops.stopTime < (SELECT stopTime FROM scheduled_stops WHERE scheduled_stops.stopID = '"+stop2+"' ORDER BY scheduled_stops.stopTime asc limit 1)";


      ResultSet rs = stmt.executeQuery(sql);

      //STEP 5: Extract data from result set
      while(rs.next()){
         //Retrieve by column name
         String stopID  = rs.getString("stopID");
         String street1 = rs.getString("street1");
         String street2 = rs.getString("street2");
         String stopTime = rs.getString("stopTime");

         //Display values
         System.out.print("Stop ID: " + stopID);
         System.out.print(", Name: " + street1 + "/" +street2);
         System.out.println(", Time: " + stopTime);
      }

}

java.sql.SQLException: You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use near'
scheduled_stops.routeNumber = '051' AND scheduled_stops.direction = 'Northbound''
at line 1
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:2975)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1600)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:1695)
at com.mysql.jdbc.Connection.execSQL(Connection.java:3020)
at com.mysql.jdbc.Connection.execSQL(Connection.java:2949)
at com.mysql.jdbc.Statement.executeQuery(Statement.java:959)
at TransitManager.stopsOnRoute(TransitManager.java:460)
at TransitManager.main(TransitManager.java:104)

【问题讨论】：

问题出在你正在做的 sql 查询中，在将其添加到 java 代码之前尝试使用 phpmyadmin 或 mysql 工作台进行测试
在查询的每一行末尾添加空格。
好的，感谢 cmets。在测试 mySQL 工作台时，我会更加注意空格

标签： java mysql sql eclipse

【解决方案1】：

在生成查询时请记住一件事，首先在 sql shell 或工具中运行它，然后在代码中使用适当的间距和字符串操作来实现。

 sql = "SELECT DISTINCT bus_stops.stopID, street1, street2 FROM bus_stops INNER JOIN scheduled_stops ON bus_stops.stopID = scheduled_stops.stopID"+
                  " WHERE scheduled_stops.routeNumber = '"+route+"' "+
                  " AND scheduled_stops.direction = '"+dir+"' "+
                  " AND scheduled_stops.stopTime > (SELECT stopTime FROM scheduled_stops WHERE scheduled_stops.stopID = '"+stop1+"' ORDER BY scheduled_stops.stopTime asc limit 1)"+ 
                  " AND scheduled_stops.stopTime < (SELECT stopTime FROM scheduled_stops WHERE scheduled_stops.stopID = '"+stop2+"' ORDER BY scheduled_stops.stopTime asc limit 1)";

【讨论】：

【解决方案2】：

检查sql-String 第一行和第四行末尾是否缺少空格。

【讨论】：

感谢，我会小心空格

【解决方案3】：

stopID 和 WHERE 之间缺少一个空格。

【讨论】：

感谢您的评论，确实会注意间距

【解决方案4】：

正确使用 Whitspaces。试试这个：

sql = "SELECT DISTINCT bus_stops.stopID, street1, street2 FROM bus_stops INNER JOIN scheduled_stops ON bus_stops.stopID = scheduled_stops.stopID "+
              "WHERE scheduled_stops.routeNumber = '"+route+"' "+
              "AND scheduled_stops.direction = '"+dir+"' "+
              "AND scheduled_stops.stopTime > (SELECT stopTime FROM scheduled_stops WHERE scheduled_stops.stopID = '"+stop1+"' ORDER BY scheduled_stops.stopTime asc limit 1) "+ 
              "AND scheduled_stops.stopTime < (SELECT stopTime FROM scheduled_stops WHERE scheduled_stops.stopID = '"+stop2+"' ORDER BY scheduled_stops.stopTime asc limit 1)";

【讨论】：