提取数据 2 年并将数字转换为月份

Question

我有下表，我想加入以创建日期的月份和年份分开（因为我没有日期，因此可以将其设置为第一个）

测量 mm yyyy 15000 1 2014 16000 2 2014 15000 5 2013 16000 3 2014 15000 4 2014 16000 5 2014 15000 6 2013 16000 7 2012

所以我希望输出为：

15000 01/01/2014
16000 01/02/2014

等等

仅限过去 2 年。

这可能吗？

谢谢

Answer 1

SELECT Measurement,DT FROM
(
    SELECT Measurement,DENSE_RANK() OVER(ORDER BY YYYY DESC) RNK,
    CONVERT(varchar(11),'01'+'/'+CAST(MM AS VARCHAR(2))+'/'+CAST(YYYY AS VARCHAR(4)),103) DT
    FROM #TEMP
)TAB
WHERE RNK IN(1,2)

• SQL FIDDLE

更新

我正在根据您的新要求进行更新

在这里，我们将获得整个月和LEFT JOIN 与您的餐桌

;WITH CTE1 AS
(
    SELECT 1 ID, CAST('01/01/2013' AS DATE) DT
    UNION ALL 
    SELECT ID+1,DATEADD(MONTH,1,DT) FROM CTE1
    WHERE ID<12
)
SELECT ID,DATENAME(MONTH,DT) [MONTH],TP.*,
DENSE_RANK() OVER(ORDER BY YYYY DESC) RNK
INTO #NEWTABLE
FROM CTE1
LEFT JOIN TEMP TP ON CAST(TP.MM AS NUMERIC(3,0)) = CAST(CTE1.ID AS NUMERIC(3,0)) 

现在我们声明 2 个变量，第一个变量用于获取值以将月份的行显示为列，第二个变量用于替换 NULL with zero

DECLARE @cols NVARCHAR (MAX)
DECLARE @NullToZeroCols NVARCHAR (MAX)

SELECT @cols = COALESCE (@cols + ',[' + [MONTH] + ']', 
              '[' + [MONTH] + ']')
               FROM    (SELECT DISTINCT ID,[MONTH] FROM #NEWTABLE) PV  
               ORDER BY ID

SET @NullToZeroCols = SUBSTRING((SELECT ',ISNULL(['+[MONTH]+'],0) AS ['+[MONTH]+']' 
FROM(SELECT DISTINCT [MONTH],ID FROM #NEWTABLE GROUP BY [MONTH],ID)TAB  
ORDER BY ID  FOR XML PATH('')),2,8000)

现在我们在您的表格中选择过去两年并对其进行旋转

DECLARE @query NVARCHAR(MAX)
SET @query = 'SELECT yyyy,' + @NullToZeroCols + ' FROM 
             (
                 SELECT yyyy, [MONTH], Measurement FROM #NEWTABLE
                 WHERE RNK IN(1,2)
             ) x
             PIVOT 
             (
                 SUM(Measurement)
                 FOR [MONTH] IN (' + @cols + ')
              ) p
              WHERE yyyy IS NOT NULL
              ORDER BY yyyy;' 

EXEC SP_EXECUTESQL @query

• SQL FIDDLE