【发布时间】:2018-05-14 12:00:08
【问题描述】:
您好,我得到了我正在开发的这个应用程序,但我一直无法填充下拉框。我想在下拉框中从我的数据库中获取我的 SQL 数据,但 SQL 说“连接必须有效且打开”,但我有另一个功能,包括使用相同的代码将文本保存到我的 SQL 数据库,并且工作正常,所以我没有真的不知道哪里出了问题。
这是我的代码。
private void Form1_Load(object sender, EventArgs e)
{
try {
//This is my connection string i have assigned the database file address path
string MyConnection2 = "datasource=localhost;username=root;database=game4rent";
//This is my insert query in which i am taking input from the user through windows forms
string Query = "select Klantnummer,voornaam from game4rent.klanten";
//This is MySqlConnection here i have created the object and pass my connection string.
MySqlConnection conn = new MySqlConnection(MyConnection2);
//This is command class which will handle the query and connection object.
MySqlCommand sc = new MySqlCommand(Query, conn);
MySqlDataReader MyReader2;
MyReader2 = sc.ExecuteReader();
conn.Open();
DataTable dt = new DataTable();
dt.Columns.Add("Klantnummer", typeof(string));
dt.Columns.Add("voornaam", typeof(string));
dt.Load(MyReader2);
cbKlantenNummers.ValueMember = "Klantnummer";
cbKlantenNummers.DisplayMember = "Klantnummer,voornaam";
cbKlantenNummers.DataSource = dt;
conn.Close();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
这里是另一个有效的代码。
private void cmdOpslaanKlanten_Click(object sender, EventArgs e)
{
try
{
//This is my connection string i have assigned the database file address path
string MyConnection2 = "datasource=localhost;username=root;password=";
//This is my insert query in which i am taking input from the user through windows forms
string Query = "insert into game4rent.klanten(voornaam,achternaam,straat,huisnummer,woonplaats) values('" + this.txtVoornaam.Text + "','" + this.txtAchternaam.Text + "','" + this.txtStraat.Text + "','" + this.txtHuisnummer.Text + "','" + this.txtWoonplaats.Text + "');";
//This is MySqlConnection here i have created the object and pass my connection string.
MySqlConnection MyConn2 = new MySqlConnection(MyConnection2);
//This is command class which will handle the query and connection object.
MySqlCommand MyCommand2 = new MySqlCommand(Query, MyConn2);
MySqlDataReader MyReader2;
MyConn2.Open();
MyReader2 = MyCommand2.ExecuteReader(); // Here our query will be executed and data saved into the database.
MessageBox.Show("Save Data");
while (MyReader2.Read())
{
}
MyConn2.Close();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
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