如何计算同一行中的日总计和月总计

Question

我需要获得小额现金的每日总金额（我已经收到了）并且需要与今天的帐户代码相关的每月总金额。下面我将展示每日总计的 SQL。有人请帮我计算同一行中的每月总计。

SELECT DPetAcNo as AcNo,
   SUM(DPetAmount) as DayTotal
   FROM PettyDetail
   WHERE DPetComCode='15'
         and DPetLocCode='01'
         and DPetDate=CONVERT(date,'20181113',111)
         GROUP BY DPetAcNo

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上述查询的结果如下所示

根据结果 2018/11/13 AcNo 009111 Total = 22,995.00 009111 的实际累计 (2018/11/01 - 2018/11/13) 总计 = 136,265.42

Answer 1

regbas 答案的修改版本应该会表现得更好，因为它不考虑这么多行：

SELECT DPetAcNo as AcNo,
   SUM(case when DPetDate=CONVERT(date,'20181113',111) then DPetAmount else 0 end) as DayTotal,
   SUM(DPetAmount) as MonthTotal
   FROM PettyDetail
   WHERE DPetComCode='15'
         and DPetLocCode='01'
         and DPetDate >= '2018-11-01'
         AND DPetDate < '2018-12-01'
         AND DPetAcNo IN (select dpetacno from pettydetail WHERE DPetComCode='15'
         and DPetLocCode='01'
         and DPetDate = '2018-11-13')
         GROUP BY DPetAcNo

如果你想跳过 CONVERT 代码混乱，Sqlserver 会隐式地将“yyyy-mm-dd”字符串转换为日期。拥有涵盖日期、comcode、loccode、帐户和金额的索引也会有所帮助

——

解决此问题的另一种方法是使用您似乎已经为 daytotal 和 cumtotal 编写的查询，如下所示：

Select * from
(/*Insert your query that does daytotal into these brackets*/) d
Inner join
(/*Insert your query that does cumtotal into these brackets*/) c
ON d.DPetAcNo = c.dpetacno

Answer 2

试试这个

SELECT DPetAcNo as AcNo,
   SUM(case when DPetDate=CONVERT(date,'20181113',111) then DPetAmount else 0 end) as DayTotal,
   SUM(case when month(DPetDate)= 11 then DPetAmount else 0 end) as MonthTotal
   FROM PettyDetail
   WHERE DPetComCode='15'
         and DPetLocCode='01'
         GROUP BY DPetAcNo

Answer 3

我假设您的 DPetDate 是 Date 或 Datetime 数据类型。

您需要过滤从每月 1 日到所需日期的行。 对于同一结果的日和月总计，请在 SUM () 中使用 CASE

SELECT DPetAcNo as AcNo,
   SUM(CASE WHEN DPetDate  = '20181113' THEN DPetAmount ELSE 0 END) as DayTotal,
   SUM(DPetAmount) as MonthTotal,
   FROM PettyDetail
   WHERE DPetComCode='15'
         and DPetLocCode='01'
         and DPetDate >= '20181101'   -- from 1st of Nov
         and DPetDate <= '20181113'   -- to   13  of Nov
         GROUP BY DPetAcNo

编辑 1： 仅根据所需日期选择 AccNo。使用子查询获取月份总计。或者你也可以在CROSS APPLY

SELECT  *,
       ( SELECT SUM(DPetAmount) 
         FROM   PettyDetail x 
         WHERE  x.DPetAcNo = p.AcNo 
         AND    x.DPetComCode = '15' 
         AND    x.DPetLocCode = '01'
         AND    x.DPetDate >= '20180101' 
         AND    x.DPetDate <= '20181113') as MonthTotal
FROM
(
    SELECT DPetAcNo as AcNo,
       SUM(CASE WHEN DPetDate  = '20181113' THEN DPetAmount ELSE 0 END) as DayTotal
       FROM PettyDetail p
       WHERE DPetComCode='15'
             and DPetLocCode='01'
             and DPetDate = '20181113'   -- for 13  of Nov only
             GROUP BY DPetAcNo
) p

Answer 4

自我加入怎么样？

SELECT 
    DPetAcNo AcNo
,   DayTotal
,   SUM(DPetAmount) MonthlyTotal
FROM PettyDetail pd
JOIN (
    SELECT 
        DPetAcNo AcNo
    ,   SUM(DPetAmount) DayTotal
    FROM 
        PettyDetail
    WHERE 
        DPetComCode='15'
    AND DPetLocCode='01'
    AND DPetDate = CONVERT(DATE,'20181113',111)
    GROUP BY DPetAcNo
) pd2 ON pd2.AcNo = dp.DPetAcNo
WHERE 
    MONTH(DPetDate) = MONTH(CONVERT(DATE,'20181113',111)) 
AND YEAR(DPetDate)  = YEAR(CONVERT(DATE,'20181113',111))
GROUP BY DPetAcNo, DayTotal