获取一周中接下来 n 天的列表？答案

【问题标题】：Getting a list of the next n days of the week?获取一周中接下来 n 天的列表？
【发布时间】：2018-06-30 00:08:20
【问题描述】：

我有两列工作日和这些工作日之间的天数，如下所示：

Monday  | Saturday    | 13
Tuesday | Friday      | 54
Friday  | Wednesday   | 10

等等。我需要使用 SQL 来创建另一个包含两个工作日之间所有 13 或 54 个工作日的字符串的列。所以像“星期一，星期二，星期三，......星期一，星期二......星期五，星期六”

如何做到这一点？谢谢。

【问题讨论】：

您使用的是什么 SQL Server？什么客户端编程语言？
我正在使用 BigQuery，使用标准 SQL。

标签： sql string parsing google-bigquery

【解决方案1】：

以下是 BigQuery 标准 SQL

#standardSQL
SELECT start, duration,
  REGEXP_EXTRACT(
    REPEAT('Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,',CAST(duration/7+1 AS INT64)),
    CONCAT(r'', start, r'(?:(?:,\w+){', CAST(duration - 1 AS STRING), '})')
  ) days_list
FROM `project.dataset.table`

您可以使用您问题中的虚拟数据来测试/玩它，如下所示

#standardSQL
WITH `project.dataset.table` AS (
  SELECT 'Monday' start, 'Saturday' finish, 13 duration UNION ALL
  SELECT 'Tuesday', 'Friday', 54 UNION ALL
  SELECT 'Friday', 'Wednesday', 10 
)
SELECT start, duration,
  REGEXP_EXTRACT(
    REPEAT('Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,', CAST(duration / 7 + 1 AS INT64) ), 
    CONCAT(r'', start, r'(?:(?:,\w+){', CAST(duration - 1 AS STRING), '})')
  ) days_list
FROM `project.dataset.table`

结果为

Row start   duration    days_list    
1   Monday  13  Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday   
2   Tuesday 54  Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday    
3   Friday  10  Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday

【讨论】：