PostgreSQL 中 JSON 数组的复杂查询答案

【问题标题】：Complex query with JSON array in PostgreSQLPostgreSQL 中 JSON 数组的复杂查询
【发布时间】：2021-04-22 00:35:20
【问题描述】：

我的 Postgres DB 中有一个视图，其中包含用于拼图和拼图 ID 的单词/线索对，称为“allwords”：

    word  |  clue       |  puz_id
    =============================
    dog   |  animal     |  1
    -----------------------------
    cat   |  animal     |  1
    -----------------------------
    apple |  fruit      |  2
    -----------------------------
    etc...

现在我想查看数据库中与 JSON 字符串中传递的单词/线索对数组的匹配，这可能看起来像

[{"word": "dog", "clue": "%animal%"}, {"word": "cat", "clue": "%ani%"}, {"word": "appl%", "clue": "fruit"}]

我在 PostgreSQL 中使用jsonb_to_recordset 将 JSON 转换为表，然后我的最终查询如下所示：

select a."word", a."clue", count(a.puz_id) as "matched"
from allwords a
where exists (
    select 1 from 
    jsonb_to_recordset('[{"word": "dog", "clue": "%animal%"}, {"word": "cat", "clue": "%ani%"}, {"word": "appl%", "clue": "fruit"}]'::jsonb) 
    as jsdata("word" text, clue text)
    where a."word" ilike jsdata."word" and a."clue" ilike jsdata.clue
    )
group by a."word", a."clue"
order by "matched" desc;

我现在得到的结果是按数据库表中的匹配单词/线索分组的：

    word  |  clue       |  matched
    =============================
    dog   |  animal     |  5 (e.g.)
    -----------------------------
    cat   |  animal     |  3 (e.g.)
    -----------------------------
    apple |  fruit      |  1 (e.g.)
    -----------------------------

问题是：我怎样才能得到一个由 matching 和 matched 词/线索对分组的相似匹配表？我希望是这样的：

    matched_word  |  matched_clue      | matching_word  |  matching_clue       |  matched
    =======================================================================================
    dog           |  %animal%          | dog            |  animal              |  5
    ---------------------------------------------------------------------------------------
    cat           |  %ani%             | cat            |  animal              |  3
    ---------------------------------------------------------------------------------------
    appl%         |  fruit             | apple          |  fruit               |  1
    ---------------------------------------------------------------------------------------

【问题讨论】：

标签： sql json postgresql

【解决方案1】：

明白了！查询应在ilike 上使用join：

select jsdata."word", jsdata.clue, count(a.puz_id) as "matched" from 
allwords a
join 
    jsonb_to_recordset('[{"word": "dog", "clue": "%animal%"}, {"word": "cat", "clue": "%ani%"}, {"word": "appl%", "clue": "fruit"}]'::jsonb) 
    as jsdata("word" text, clue text)
    on (a."word" ilike jsdata."word" and a.clue ilike jsdata.clue) -- THIS WORKS!!!
group by jsdata."word", jsdata.clue
order by "matched" desc;

【讨论】：