从表 2 中删除表 1 中存在的行并将这些额外的行添加到表 1答案

【问题标题】：Deleting the row from table 2 that exist in table 1 and add these extra rows to table1从表 2 中删除表 1 中存在的行并将这些额外的行添加到表 1
【发布时间】：2021-02-12 19:47:57
【问题描述】：

所以我写了这个查询。我想获取不在第一个数据集中的空数据。

第一次查询返回 34 个用户
第二次查询返回 43 个用户
我需要将额外的 10 个用户添加到第一个

select projects_users_duration.user_id,
       projects_users_duration.engineer_name,
       COALESCE(sum(projects_users_duration.duration) FILTER ( WHERE projects_users_duration.project_type = 1 ), 0) as billed,
       COALESCE(sum(projects_users_duration.duration) FILTER ( WHERE projects_users_duration.project_type != 1 ), 0) as un_billed
    from
(select users_in_team.user_id, users_in_team.engineer_name, tt.month, tt.year, t.duration,
       (select up.project_type_id from users_project up where id = tt.project_id) as project_type
from (select uu.id as user_id, pgp_sym_decrypt(uu.name, '1234') as engineer_name
      from users_team_members as utm
               left join users_user uu on uu.id = utm.user_id
      where utm.team_id in (1, 2)) as users_in_team
         left join timetracker_timesheet tt on users_in_team.user_id = tt.user_id
         left join timetracker_timesheetentry t on tt.id = t.timesheet_id
where tt.month in (1)
  and tt.year = 2021
  and tt.status = 'approved') as projects_users_duration
group by projects_users_duration.user_id, projects_users_duration.engineer_name

select uu.id as user_id, pgp_sym_decrypt(uu.name, '1234') as engineer_name, 0 as billed, 0 as un_billed
      from users_team_members as utm
               left join users_user uu on uu.id = utm.user_id
      where utm.team_id in (1, 2)

第一个数据集也应该包含空数据，但我认为这是因为 where 子句。

【问题讨论】：

标签： sql database postgresql

【解决方案1】：

要从第二个查询中获取第一个查询中不可用的所有行：

with cte as(select projects_users_duration.user_id,
       projects_users_duration.engineer_name,
       COALESCE(sum(projects_users_duration.duration) FILTER ( WHERE projects_users_duration.project_type = 1 ), 0) as billed,
       COALESCE(sum(projects_users_duration.duration) FILTER ( WHERE projects_users_duration.project_type != 1 ), 0) as un_billed
    from
(select users_in_team.user_id, users_in_team.engineer_name, tt.month, tt.year, t.duration,
       (select up.project_type_id from users_project up where id = tt.project_id) as project_type
from (select uu.id as user_id, pgp_sym_decrypt(uu.name, '1234') as engineer_name
      from users_team_members as utm
               left join users_user uu on uu.id = utm.user_id
      where utm.team_id in (1, 2)) as users_in_team
         left join timetracker_timesheet tt on users_in_team.user_id = tt.user_id
         left join timetracker_timesheetentry t on tt.id = t.timesheet_id
where tt.month in (1)
  and tt.year = 2021
  and tt.status = 'approved') as projects_users_duration
group by projects_users_duration.user_id, projects_users_duration.engineer_name)

select uu.id as user_id, pgp_sym_decrypt(uu.name, '1234') as engineer_name, 0 as billed, 0 as un_billed
      from users_team_members as u

tm left join users_user uu on uu.id = utm.user_id 其中 utm.team_id 在 (1, 2) 而 uu.id 不在（从 cte 中选择 user_id）

现在您可以在任何表中插入这些行，也可以根据需要删除它们。

【讨论】：

我使用 with 解决了这个问题，谢谢。但上述方法只给了我表 2 的额外内容。
很高兴知道您的问题已经解决。最美好的祝愿

【解决方案2】：

with team_members as (
    select uu.id                                                as user_id,
           pgp_sym_decrypt(uu.name, '12345') as engineer_name,
           0                                                    as billed,
           0                                                    as un_billed,
           0                                                    as total
    from users_team_members as utm
             left join users_user uu on uu.id = utm.user_id
    where utm.team_id in (1, 2)
      and (uu.end_date is null or uu.end_date > now())
    group by uu.id
),
     individual_data as (
         select projects_users_duration.user_id,
                projects_users_duration.engineer_name,
                COALESCE(sum(projects_users_duration.duration)
                         FILTER ( WHERE projects_users_duration.project_type = 1 ), 0)
                                                      as billed,
                COALESCE(sum(projects_users_duration.duration)
                         FILTER ( WHERE projects_users_duration.project_type != 1 ), 0)
                                                      as unbilled,
                sum(projects_users_duration.duration) as total
         from (select users_in_team.user_id,
                      users_in_team.engineer_name,
                      tt.month,
                      tt.year,
                      t.duration,
                      (select up.project_type_id from users_project up where id = tt.project_id) as project_type
               from team_members as users_in_team
                        left join timetracker_timesheet tt on users_in_team.user_id = tt.user_id
                        left join timetracker_timesheetentry t on tt.id = t.timesheet_id
               where tt.month in (1, 2, 3)
                 and tt.year = 2021
                 and tt.status in ('approved')) as projects_users_duration
         group by projects_users_duration.user_id, projects_users_duration.engineer_name
     )

    (select *
     from team_members
     where user_id not in (select user_id from individual_data)
     union
     select *
     from individual_data) order by total desc

【讨论】：