需要合并mysql表中的两列日期和时间，并找出与当前日期和时间的差异

Question

实际上我需要列出从邮件日期和时间开始不超过 24 小时的数据。

我已将邮件日期和邮件时间存储在数据库的 2 个不同列中。

请从我写的以下查询中提供您的有效输入，

      $CTime = strtotime(date('Y-m-d H:i:s'));
      //getting the 24 hours back time
      $Btime = $CTime - 86400;

      $listingInvoice = mysqli_query($conn, "SELECT *, (CONCAT(MailDate, MailTime)) AS MailDT FROM approved WHERE JobStatus='MailedToClient' && MailDT > '$Btime'");

Answer 1

请检查从数据库不同列中获取的日期和时间，并找到该值，即不超过当前时间的 24 小时。

      date_default_timezone_set('Asia/Kolkata');

      //getting the current date and time...
      $CTime = date('Y-m-d H:i:s');

      //convert to string the current date and time...
      $CSTime = strtotime(date('Y-m-d H:i:s'));

      //Minus the 86400(value of 24 Hrs in seconds) in the converted date and time string
      $BStime = $CSTime - 86400;

      //getting the value of date and time before 24 Hrs...
      $BTime = date('Y-m-d H:i:s', $BStime);

      //Now the query is...
      $reject = mysqli_query($conn, "SELECT * FROM approved WHERE JobStatus='MailToClient' && MailDateTime BETWEEN '$BTime' AND '$CTime'");
      $row = mysqli_num_rows($reject);
      if ($row == '0')
      {
        echo "No Jobs Mails SENT for the Last 24 Hrs";
      }
      else
      {
        ....
      }