【发布时间】:2012-02-23 01:23:18
【问题描述】:
希望有人能帮助我理解这一点,我完全迷失了,似乎根本无法理解这一点。
我有一个从数据库中提取信息的应用程序,此时,Android 连接到一个 PHP 页面,结果打印在应用程序上,如下所示:
{"offer":"Half Price Drinks", "Day":"Monday"}
{"offer":"Half Price Drinks", "Day":"Tuesday"}
我需要将其转换为列表视图,谁能告诉我如何做到这一点?
我已经把连接到php页面的页面放进去,并把这些信息拉进去。
public class BarsActivity extends Activity {
TextView txt;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
// Create a crude view - this should really be set via the layout resources
// but since its an example saves declaring them in the XML.
LinearLayout rootLayout = new LinearLayout(getApplicationContext());
txt = new TextView(getApplicationContext());
rootLayout.addView(txt);
setContentView(rootLayout);
// Set the text and call the connect function.
txt.setText("Connecting...");
//call the method to run the data retreival
txt.setText(getServerData(KEY_121));
}
public static final String KEY_121 = "http://10.0.2.2/SocialCrawler/content.php"; //i use my real ip here
private String getServerData(String returnString) {
InputStream is = null;
String result = "";
//the year data to send
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("day","Monday"));
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(KEY_121);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection "+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
//parse json data
try{
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++){
JSONObject json_data = jArray.getJSONObject(i);
Log.i("log_tag","day: "+json_data.getString("day")+
", offer: "+json_data.getString("offer")
);
//Get an output to the screen
returnString += "\n\t" + jArray.getJSONObject(i);
}
}catch(JSONException e){
Log.e("log_tag", "Error parsing data "+e.toString());
}
return returnString;
}
}
【问题讨论】:
-
老实说。互联网上有很多例子。 p-xr.com/… 和 mobile.dzone.com/news/android-tutorial-how-parse 和很多在这个网站上
-
数据如何映射到 ListView?一个 View 会显示今天的优惠,还是 ListView 会显示今天的优惠和即将推出的优惠?
-
它只会显示当天的报价列表,我有它,所以用户选择了一天,然后将这一天传递给 PHP 文件,该文件返回当天的报价。
-
也许有人可以帮助我完成教程,我已经获取了源代码并尝试输入我的信息,我是否正确地说唯一需要更改的是 url Main.java 上的文件的 id、eqid 和幅度,它们必须更改为我数据库中的变量吗?
标签: php android sql database json