如何将具有排名值的列转换为oracle中的行答案

【问题标题】：How to convert column with Rank Value into rows in oracle如何将具有排名值的列转换为oracle中的行
【发布时间】：2019-10-07 03:38:28
【问题描述】：

我有一些查询，返回以下数据：

Month Year EMP_ID EMP_NAME RANK
Jan   2019  1       EmpName1    1
Jan   2019  2       EmpName2    2
Jan   2019  3       EmpName3    3
Jan   2019  4       EmpName4    4
Jan   2019  5       EmpName5    5
FEB   2019  1       EmpName1    1
FEB   2019  2       EmpName2    2
FEB   2019  3       EmpName3    3
FEB   2019  4       EmpName4    4
FEM   2019  5       EmpName5    5

我想以以下格式显示此数据：

Month Year  Rank1        Rank2     Rank3      Rank4       Rank5
Jan   2019 EmpName1    EmpNAme2   EmpName3  EmpName4    EmpName5
Feb   2019 EmpName1    EmpNAme2   EmpName3  EmpName4    EmpName5

【问题讨论】：

谷歌“SQL 数据透视表”

标签： sql oracle pivot

【解决方案1】：

如果版本 Oracle 11+ 使用枢轴

with tbl as
(SELECT 'JAN' mon,   '2019' y, '1' rn, 'EmpName1' name from dual
UNION ALL 
select 'JAN', '2019', '2', 'EmpName2' from dual 
union all 
select 'JAN', '2019', '3', 'EmpName3' from dual
union all
select 'JAN', '2019', '4', 'EmpName4' from dual
union all
select 'JAN', '2019', '5', 'EmpName5' from dual
union all
select 'FEB', '2019', '1', 'EmpName1' from dual
union all
select 'FEB', '2019', '2', 'EmpName2' from dual
union all
select 'FEB', '2019', '3', 'EmpName3' from dual
union all
select 'FEB', '2019', '4', 'EmpName4' from dual
union all
select 'FEB', '2019', '5', 'EmpName5' from dual)
select *  
from (select mon, y, rn, name 
from tbl)
pivot
(
  MAX(name)
  FOR rn
  IN ('1', '2', '3', '4', '5')
)
ORDER BY 1

如果是 10 克

with tbl as
(SELECT 'JAN' mon,   '2019' y, '1' rn, 'EmpName1' name from dual
UNION ALL 
select 'JAN', '2019', '2', 'EmpName2' from dual 
union all 
select 'JAN', '2019', '3', 'EmpName3' from dual
union all
select 'JAN', '2019', '4', 'EmpName4' from dual
union all
select 'JAN', '2019', '5', 'EmpName5' from dual
union all
select 'FEB', '2019', '1', 'EmpName1' from dual
union all
select 'FEB', '2019', '2', 'EmpName2' from dual
union all
select 'FEB', '2019', '3', 'EmpName3' from dual
union all
select 'FEB', '2019', '4', 'EmpName4' from dual
union all
select 'FEB', '2019', '5', 'EmpName5' from dual)
select 
mon,
y,
min(decode(rn, 1, nm, NULL)) Rank1 ,
min(decode(rn, 2, nm, NULL)) Rank2 ,
min(decode(rn, 3, nm, NULL)) Rank3 ,
min(decode(rn, 4, nm, NULL)) Rank4 ,
min(decode(rn, 5, nm, NULL)) Rank5 
from
 (
  select
  tbl.mon,
  tbl.y,
  tbl.rn,
  max(name) nm
  from
  tbl
  group by tbl.mon, tbl.y, tbl.rn
 )
group by mon, y

【讨论】：

这么好的和全面的答案。

【解决方案2】：

只需使用 Conditional Aggregation 和 case..when 表达式：

select Month, Year,
       max( case when emp_id = 1 then Emp_Name end ) as EmpName1,
       max( case when emp_id = 2 then Emp_Name end ) as EmpName2,
       max( case when emp_id = 3 then Emp_Name end ) as EmpName3,
       max( case when emp_id = 4 then Emp_Name end ) as EmpName4,
       max( case when emp_id = 5 then Emp_Name end ) as EmpName5
  from tab
 group by Month, Year

【讨论】：