Oracle SQL 行到具有分组依据和总和的列答案

【问题标题】：Oracle SQL rows to column with group by and sumOracle SQL 行到具有分组依据和总和的列
【发布时间】：2021-01-31 09:30:20
【问题描述】：

我有一个包含以下数据的表格。

ID    Name     DiscountGroup Discount DicountCategory
A     XXX      G025          25        MANGMNT
A     XXX      T005           5        HIGH GPA
A     XXX      T010          10        
B     XXXB     G040          40        SOMETXT
B     XXXB     T005           5        HIGH GPA

我想将数据显示为

ID    Name     PermanentDiscount Cateogry TempDiscount 
A     XXX      25                MANGMNT  15
B     XXXB     40                SOMETXT   5

即 1 行中的永久和临时折扣。所有永久折扣均以 GXXX 开头，后跟 3 位数。同样，所有临时折扣都以 TXXX 开头，后跟 3 位数字，其中 XXX 表示实际折扣。一个ID可以有多个临时折扣，但只能有一个永久折扣。我尝试使用

SELECT *
  FROM tableA
PIVOT (
  MAX(Discount) FOR DiscountGroup IN ('')
);

但我无法找出列表中的值。

【问题讨论】：

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标签： sql oracle pivot pivot-table

【解决方案1】：

您可以为每个 ID/姓名添加一个包含临时折扣总和的列，然后过滤具有永久折扣的行。

select ID, Name, PermanentDiscount, Cateogry, TempDiscount
from (
    select
        DiscountGroup, ID, Name,
        Discount as PermanentDiscount,
        DicountCategory as Cateogry,
        sum(case when DiscountGroup like 'T%' then Discount else 0 end) over(partition by ID, Name) as TempDiscount
    from table
)
where DiscountGroup like 'G%'
order by ID, Name;

【讨论】：

【解决方案2】：

这应该可行：

WITH sample_data AS 
   ( SELECT 'A' AS id, 'XXX' AS name, 'G025' AS DiscountGroup, 25 AS Discount, 'MANGMNT' AS DiscountCategory FROM DUAL UNION ALL
     SELECT 'A' AS id, 'XXX' AS name, 'T005' AS DiscountGroup, 5 AS Discount, 'HIGH GPA' AS DiscountCategory FROM DUAL UNION ALL
     SELECT 'A' AS id, 'XXX' AS name, 'T010' AS DiscountGroup, 10 AS Discount, NULL AS DiscountCategory FROM DUAL UNION ALL
     SELECT 'B' AS id, 'XXXB' AS name, 'G040' AS DiscountGroup, 40 AS Discount, 'SOMETXT' AS DiscountCategory FROM DUAL UNION ALL
     SELECT 'B' AS id, 'XXXB' AS name, 'T005' AS DiscountGroup, 5 AS Discount, 'HIGH GPA' AS DiscountCategory FROM DUAL
   )
SELECT id,
       name,
       MAX(CASE WHEN DiscountGroup = 'G' THEN Discount ELSE 0 END) AS PermanentDiscount,
       MAX(CASE WHEN DiscountGroup = 'G' THEN Cateogry ELSE NULL END) AS Cateogry,
       SUM(CASE WHEN DiscountGroup = 'T' THEN Discount ELSE 0 END) AS TempDiscount
  FROM ( SELECT id,
                name,
                SUBSTR(DiscountGroup, 1, 1) AS DiscountGroup,
                Discount,
                FIRST_VALUE(DiscountCategory) OVER(PARTITION BY id, name, SUBSTR(DiscountGroup, 1, 1) ORDER BY Discount DESC) AS Cateogry
           FROM sample_data
       )
  GROUP BY id, name
  ORDER BY id, name;

结果：

I NAME PERMANENTDISCOUNT CATEOGRY TEMPDISCOUNT
- ---- ----------------- -------- ------------
A XXX                 25 MANGMNT            15
B XXXB                40 SOMETXT             5

【讨论】：

【解决方案3】：

我认为它应该适合你 =>

WITH CTE AS(
SELECT ID,SUM(Discount) TempDiscount
FROM tableA 
WHERE DiscountGroup LIKE 'T%' 
GROUP BY ID )
SELECT a.*,c.TempDiscount FROM
CTE c
INNER JOIN tableA a ON a.ID=c.ID AND a.DiscountGroup LIKE 'G%'

注意：你可以在这里查看我的代码 => LINK

【讨论】：

【解决方案4】：

我在雪花中运行这个。

select id
      ,max(Name)
      ,sum(case when discountgroup like 'G%' then discount else 0 end) Permanentdiscount
      ,max(case when discountgroup like 'G%' then discountcategory end ) category
      ,sum(case when discountgroup like 'T%' then discount else 0 end) Temporarydiscount
from SAMPLE_DATA
      group by id;

【讨论】：