加速oracle SQL查询答案

【问题标题】：Speed up oracle SQL query加速oracle SQL查询
【发布时间】：2019-02-06 09:55:23
【问题描述】：

我有一个查询，我正在尝试优化一个运行需要 6 分钟的查询（DS1 有 200k 行，DS2 也有 200k 行）。我想知道甲骨文大师是否可以看到任何优化？我绝不是专家，更像是一个业余爱好者......问题看起来像分组部分花费的时间最长......

WITH DS1 AS
  (SELECT
    /*+ PARALLEL */
    *
  FROM PD1
  WHERE TYPE      = 'TSY'
  AND SOURCE = 'A'
  ),
  DS2 AS
  (SELECT
    /*+ PARALLEL */
    *
  FROM PD1
  WHERE TYPE     = 'LGL'
  AND SOURCE = 'B'
  ),
  Q AS
  (SELECT DS1.ID  AS DS1_ID,
    DS1.CODE  AS DS1_CODE,
    DS2.CODE  AS DS2_CODE,
    DS2.ID        AS DS2_ID,
    DS1.TYPE        AS TYPE1,
    DS2.TYPE        AS TYPE2,
    DS1.SOURCE AS SS1,
    DS2.SOURCE AS SS2,
    DS1.ATTRIBUTE,
    DS1.ATTRIBUTE_VAL,
    DS1.ATT_AND_VAL
  FROM DS1
  JOIN DS2
  ON DS1.ATT_AND_VAL = DS2.ATT_AND_VAL
  ) ,
  GROUPINGS AS
  (SELECT
    /*+no_merge */
    DS1_ID                  AS BASE_ID ,
    DS1_CODE               AS BASE_CODE,
    DS2_CODE               AS TARGET_CODE,
    COUNT(DISTINCT(DS2_ID)) AS COUNT_OF_TARGET_ID
  FROM Q
  GROUP BY DS1_ID,
    DS1_CODE,
    DS2_CODE
  )
SELECT *
FROM GROUPINGS
ORDER BY BASE_ID,
  BASE_CODE,
  TARGET_CODE;

【问题讨论】：

首先要做的是检查解释计划。请获取解释计划输出（作为文本，而不是图像）并将其包含在您的问题中。
另外，PD1 表的主键/唯一键是什么？

标签： sql oracle performance query-optimization

【解决方案1】：

我很想通过删除所有公用表表达式和提示来简化现有查询。像这样：

SELECT
    DS1_ID                     AS BASE_ID
  , DS1_CODE                   AS BASE_CODE
  , DS2_CODE                   AS TARGET_CODE
  , COUNT( DISTINCT (DS2_ID) ) AS COUNT_OF_TARGET_ID
FROM (
    SELECT
        DS1.ID     AS DS1_ID
      , DS1.CODE   AS DS1_CODE
      , DS2.CODE   AS DS2_CODE
      , DS2.ID     AS DS2_ID
    FROM PD1 DS1
    JOIN PD1 DS2 ON DS1.ATT_AND_VAL = DS2.ATT_AND_VAL
                AND DS2.TYPE = 'LGL'
                AND DS2.SOURCE = 'B'
    WHERE DS1.TYPE = 'TSY'
    AND DS1.SOURCE = 'A'
    ) Q
GROUP BY
    DS1_ID
  , DS1_CODE
  , DS2_CODE
ORDER BY
    BASE_ID
  , BASE_CODE
  , TARGET_CODE
;

如果这需要几分钟才能运行，那么我建议您需要添加索引。首先要做的是制定解释计划，以确定是否使用任何索引来缩小后续步骤的范围。

【讨论】：