【发布时间】:2019-06-23 13:00:55
【问题描述】:
创建触发器时没有错误。但是当我触发它时,会显示一条错误消息,表明该表正在发生变化。如何解决表变异的问题?
CREATE OR REPLACE TRIGGER tgr_invoice
AFTER UPDATE OF discharge_date
ON Admission
FOR EACH ROW
DECLARE
doc_fee NUMBER(5);
nights_stayed NUMBER(4);
room_price NUMBER(5);
room_fee NUMBER(9);
med_fee NUMBER(7, 2);
units_prescribed NUMBER(3);
price_per_unit NUMBER(7, 2);
total_fee NUMBER(8,2);
BEGIN
SELECT consult_fee INTO doc_fee
FROM Doctor
WHERE staff_id IN (SELECT seen_by FROM Admission
WHERE patient_id = :NEW.patient_id
AND admission_date = :NEW.admission_date);
SELECT (discharge_date - admission_date) INTO nights_stayed
FROM Admission
WHERE patient_id = :NEW.patient_id
AND admission_date = :NEW.admission_date;
SELECT room_price INTO room_price
FROM Room
WHERE room_no IN (SELECT room_no FROM Admission
WHERE patient_id = :NEW.patient_id
AND admission_date = :NEW.admission_date);
SELECT units_prescribed INTO units_prescribed
FROM Prescription
WHERE patient_id = :NEW.patient_id
AND prescription_date = :NEW.admission_date;
SELECT price_per_unit INTO price_per_unit
FROM Medicine
WHERE med_id IN (SELECT med_id FROM Prescription
WHERE patient_id = :NEW.patient_id
AND prescription_date = :NEW.Admission_date);
room_fee := room_price * nights_stayed;
med_fee := units_prescribed * price_per_unit;
total_fee := room_fee + doc_fee + med_fee;
INSERT INTO Invoice VALUES(seq_inv_no.NEXTVAL, :NEW.patient_id,
:NEW.admission_date, doc_fee, room_fee, med_fee, total_fee);
END;
/
当我更新准入表并输入出院日期时,出现错误'表SYSTEM.ADMISSION正在变异,触发器/函数可能看不到它'
【问题讨论】:
-
如果您描述了您尝试实现的逻辑,将会有所帮助。样本数据和所需结果的帮助。
-
您不应在
SYSTEM(或任何其他Oracle 系统模式)中创建任何用户表或其他对象。为您的应用程序创建一个用户并在那里创建您的对象。
标签: oracle plsql triggers database-trigger