【发布时间】:2020-09-10 12:56:11
【问题描述】:
我有一张表,我在该表上构建了 ETL 服务。货物记录(到达/离开)到表。我已经完成了我的表将被删除。当项目标识符第二次到达数据库时,两条记录都被删除。
label cost time
x2 29 14/5/2020 01:00:00
x3 20 14/5/2020 01:02:00
x2 29 15/5/2020 03:12:02
现在 ETL 服务删除记录(每 30 秒):
label cost time
x3 20 14/5/2020 01:02:00
我使用函数删除它:
with todelete as (
select *, count(*) over (partition by label) as cnt, ROW_NUMBER() over (partition by label order by time DESC) as r_number
from Table1
)
delete from todelete
where cnt >= 2
还有另一个问题。而说到餐桌,这只意味着价格的变化。
变体 1:
label cost time
x2 29 14/5/2020 01:00:00
x3 20 14/5/2020 01:02:00
x2 30 15/5/2020 03:12:02
现在“删除函数”和
我的目标:
label cost time
x3 20 14/5/2020 01:02:00
x2 30 15/5/2020 03:12:02
我不知道如何在删除函数中处理这两件事。
【问题讨论】:
-
ROW_NUMBER() over (partition by label order by time DESC) as r_number有什么用?
标签: sql sql-server ssis etl