通过比较sql server中同一张表的每条记录返回重复答案

【问题标题】：Return duplicates by comparing each records of the same table in the sql server通过比较sql server中同一张表的每条记录返回重复
【发布时间】：2025-12-04 07:05:01
【问题描述】：

我有如下表。我想获取重复的记录。这里是条件

状态 = 1 的订阅者，即活跃，并且通过比较 start_date 和 end_date 在当前年份拥有多条记录。我在 DB 中有大约 5000 多条记录。这里展示几个示例。

id      pkg_id  start_date  end_date    status  subscriber_id
2857206 9128    8/31/2014   8/31/2015   2       3031103
2857207 9128    12/22/2015  12/22/2016  1       3031103
3066285 10308   8/5/2016    8/4/2018    1       3031103
2857206 9128    8/31/2013   8/31/2015   2       3031104
2857207 9128    10/20/2015  11/22/2016  1       3031104
3066285 10308   7/5/2016    7/4/2018    1       3031104
3066285 10308   8/5/2016    8/4/2018    2       3031105

我尝试了下面的查询，但不适用于所有记录：

SELECT  *
FROM    dbo.consumer_subsc
WHERE   status = 1
        AND YEAR(GETDATE()) >= YEAR(start_date)
        AND YEAR(GETDATE()) <= YEAR(end_date)
        AND subscriber_id IN (
        SELECT  T.subscriber_id
        FROM    ( SELECT    subscriber_id ,
                            COUNT(subscriber_id) AS cnt
                  FROM      dbo.consumer_subsc
                  WHERE     status = 1
                  GROUP BY  subscriber_id
                  HAVING    COUNT(subscriber_id) > 1
                ) T )
ORDER BY subscriber_id DESC

问题是我无法找到一种方法，可以将每一行与上述日期条件进行比较。我应该得到如下重复的结果：

id      pkg_id  start_date  end_date    status  subscriber_id
2857207 9128    12/22/2015  12/22/2016  1       3031103
3066285 10308   8/5/2016    8/4/2018    1       3031103
2857207 9128    10/20/2015  11/22/2016  1       3031104
3066285 10308   7/5/2016    7/4/2018    1       3031104

【问题讨论】：

标签： sql sql-server sql-server-2008 sql-server-2005

【解决方案1】：

只需在 where 子句中删除硬编码的用户 ID 过滤器即可。以下查询将返回预期的输出。

SELECT *
FROM dbo.consumer_subsc
WHERE  STATUS = 1
    AND year(getdate()) >= year(start_date)
    AND year(getdate()) <= year(end_date)
    AND subscriber_id IN (
        SELECT T.subscriber_id
        FROM (
            SELECT subscriber_id
                ,count(subscriber_id) AS cnt
            FROM dbo.consumer_subsc
            WHERE STATUS = 1
            GROUP BY subscriber_id
            HAVING count(subscriber_id) > 1
            ) T
        )
ORDER BY subscriber_id ,start_date

【讨论】：

请选择最适合您的答案。
我知道这一点，但预计只有重复的记录，它给了我其他非重复的数据。
删除了相同的查询我的唯一过滤器。给出重复记录和非重复记录都没有帮助。

【解决方案2】：

您可以使用 EXISTS：

 SELECT t.* FROM dbo.consumer_subsc t 
 WHERE EXISTS(SELECT subscriber_id 
        FROM dbo.consumer_subsc y 
        WHERE y.status=t.status
            AND y.subscriber_id = t.subscriber_id 
        GROUP BY subscriber_id HAVING COUNT(y.subscriber_id)>1) 
 AND STATUS = 1
 AND year(getdate()) >= year(start_date) 
 AND year(getdate()) <= year(end_date)

【讨论】：

您忘记了当前年份必须介于 start_date 和 end_date 之间。
它给我的所有记录都没有帮助！

【解决方案3】：

WITH CTE (Code, DuplicateCount)
AS
(
    SELECT subscriber_id,
    ROW_NUMBER() OVER(PARTITION BY  subscriber_id
    ORDER BY  subscriber_id) AS DuplicateCount
    FROM dbo.consumer_subsc 
    where  subscriber_id in (3031103) 
    and status=1 and year(getdate()) >= year(start_date) 
    and year(getdate()) <= year(end_date)  

)
Select * from CTE

【讨论】：

【解决方案4】：

下面的查询给出了接近预期的 O/P：

SELECT A.* FROM (SELECT t.*,Row_number() OVER(partition BY t.subscriber_id ORDER BY t.subscriber_id,t.start_date) rnk  FROM dbo.consumer_subsc t 
 WHERE EXISTS(SELECT subscriber_id 
        FROM dbo.consumer_subsc y 
        WHERE y.status=t.status
            AND y.subscriber_id = t.subscriber_id 
        GROUP BY subscriber_id HAVING COUNT(y.subscriber_id)>1) 
 AND STATUS = 1
 AND year(getdate()) >= year(start_date) 
 AND year(getdate()) <= year(end_date))A WHERE A.rnk>1

【讨论】：