【发布时间】:2016-10-25 13:27:23
【问题描述】:
我有一个查询,目的是输出所有具有"PPC" 角色的电子邮件以及这些 PPC 所属的"paygroups"。
- 有很多支付组。
- 每个
paygroup可以有多个PPCs。 - 每个
PPC可能有一个email address 1和/或一个email address 2。
当我使用测试paygroup(BOX) 时,查询工作正常,但是当我注释该行以查询所有paygroups 以返回所有paygroups 中的所有PPCs 时,我收到错误"single-row subquery returns more than one row" .
SELECT
auth.paygroup,
per.NAME,
per.email_address AS "Personal email",
per.email_address2 AS "Business email"
FROM ps_personal_data per
INNER JOIN ps_ts_ee_auth auth
ON auth.emplid=per.emplid
INNER JOIN PS_SMS_SUBSCRB_TBL SUB
ON SUB.SUBSCRIBER_ID = AUTH.PAYGROUP
WHERE 1=1
AND SUB.EFFDT = (SELECT max (SUB2.effdt) FROM PS_SMS_SUBSCRB_TBL SUB2
WHERE SUB.SUBSCRIBER_ID = SUB2.SUBSCRIBER_ID AND SUB.EFF_STATUS = 'A')
AND auth.user_name = (SELECT R1.USER_NAME FROM PS_TS_CONTACT_ROLE R1
WHERE 1=1
AND R1.contact_role = 'PPC'
--AND R1.paygroup = 'BOX' --commenting this line out causes the error. It works fine when line is active
AND R1.action_dt = (SELECT MAX (R2.action_dt)
FROM PS_TS_CONTACT_ROLE R2
WHERE 1=1
AND R1.paygroup = R2.paygroup
AND R1.contact_role =
R2.contact_role))
【问题讨论】:
-
第 1 步 - 确定您想要的行。
标签: sql oracle subquery ora-01427