如何添加特定列值的小计？答案

【问题标题】：How can I add a subtotal of specific column values?如何添加特定列值的小计？
【发布时间】：2017-08-16 19:59:09
【问题描述】：

这是数据集：

这是我的 SQL：

select f.DATE, f.PROD_STATUS,
count (*)  AS TOTAL
from PROD_TABLE  f
where DATE = '04-MAY-17'
GROUP BY f.DATE, f.PROD_STATUS

我正在尝试将 'SUCCESS' 的值作为 SQL 结果中的一列获取：

(SUCCESS = READY_1 + READY_2 + READY_3 + READY_4 + READY_5)

我希望 SQL 结果如下所示：

我怎样才能做到这一点？

【问题讨论】：

我认为你可以在 oracle 中使用pivot 来完成这项工作。

标签： sql oracle subtotal

【解决方案1】：

检查一下：

with t as (
  select 1 as ready_1, 
         2 as ready_2, 
         3 as ready_3, 
         1 as in_process,
         4 as fail,
         5 as crash,
         '5/4/2017' as dat   
  from dual 
  union all
  select 2 as ready_1, 
         2 as ready_2, 
         3 as ready_3, 
         1 as in_process,
         4 as fail,
         0 as crash,
         '5/5/2017' as dat   
  from dual 
) 

select dat, prod_stat, max(suc) over(partition by dat) as success, sum(value) over(partition by dat) as total
from (
  select dat, prod_stat, value, sum(value) over (partition by dat) as suc
  from t 
  unpivot(   
    value for prod_stat in (ready_1, ready_2, ready_3) 
  )

union all

  select dat, prod_stat, value, null as suc
  from t 
  unpivot(   
    value for prod_stat in (in_process, fail, crash) 
  )
)

结果：

DAT         PROD_STAT   SUCCESS TOTAL
5/4/2017    READY_2        6    16
5/4/2017    READY_1        6    16
5/4/2017    CRASH          6    16
5/4/2017    FAIL           6    16
5/4/2017    IN_PROCESS     6    16
5/4/2017    READY_3        6    16
5/5/2017    FAIL           7    12
5/5/2017    IN_PROCESS     7    12
5/5/2017    CRASH          7    12
5/5/2017    READY_2        7    12
5/5/2017    READY_1        7    12
5/5/2017    READY_3        7    12

【讨论】：

您好 l3rutt，感谢您的回复。问题，这个子句不是使值成为静态值吗？ 1 作为 ready_2, 1 作为 ready_3, 1 作为 in_process, 总共 8, 5 作为 suc,
数据集是现有数据。有8种生产状态，其中5种加起来等于成功（READY_1、2、3、4、5之和）
谢谢l3rutt。欣赏它