【问题标题】:SQL How to Query Total & SubtotalSQL如何查询总计和小计
【发布时间】:2021-04-01 08:16:00
【问题描述】:

我有一个如下所示的表,其中存储了 day、order_id 和 order_type。

select day, order_id, order_type
from sample_table
day order_id order_type
2021-03-01 1 offline
2021-03-01 2 offline
2021-03-01 3 online
2021-03-01 4 online
2021-03-01 5 offline
2021-03-01 6 offline
2021-03-02 7 online
2021-03-02 8 online
2021-03-02 9 offline
2021-03-02 10 offline
2021-03-03 11 offline
2021-03-03 12 offline

以下是所需的输出:

day total_order num_offline_order num_online_order
2021-03-01 6 4 2
2021-03-02 4 2 2
2021-03-03 2 2 0

有人知道如何查询以获得所需的输出吗?

【问题讨论】:

    标签: sql vertica subtotal


    【解决方案1】:

    您需要对数据进行透视。在 Vertica 中实现条件聚合的一种简单方法是使用 ::

    select day, count(*) as total_order,
           sum( (order_type = 'online')::int ) as num_online,
           sum( (order_type = 'offline')::int ) as num_offline
    from t
    group by day;
    

    【讨论】:

    • 我喜欢你的简洁:简单地将布尔值转换为 INT 以获得 0 与 1 的计数器,并将它们相加。
    【解决方案2】:

    使用casesum

    select day, 
        count(1) as total_order
        sum(case when order_type='offline' then 1 end) as num_offline_order,
        sum(case when order_type='online' then 1 end) as num_online_order
    from sample_table
    group by day
    order by day
    

    【讨论】:

      【解决方案3】:

      您还可以使用count 来聚合非空值

      select 
          day, 
          count(*) as total_order, 
          count(case when order_type='offline' then 1 else null end) as offline_orders,
          count(case when order_type='online' then 1 else null end) as online_orders 
      from sample_table 
      group by day 
      order by day;
      

      【讨论】:

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