对两个不同查询 (SQL) 的结果求和答案

【问题标题】：Sum results from two different queries (SQL)对两个不同查询 (SQL) 的结果求和
【发布时间】：2017-08-28 16:05:33
【问题描述】：

我有来自两个不同表的两个查询。一个是使用 SUM 函数制作的，另一个是使用 COUNT 函数制作的。我需要的是对他们的结果求和，这样我就可以得到一张包含总记录的表（例如表“C”）。

到目前为止，我已经尝试过这种加入，但它不起作用：

select a.origin, count(*) as received, sum(b.contacts) as sent
from bd.received a 
left join db.sent b
on a.origin=b.origin
group by b.origin

表 A（收到的联系人）

select count(*), origin from db.received group by origin

   Origin Count(*)
   Email    500
   Phone    200 
   Social   100

表 B（已发送联系人）

select sum(contacts), origin from db.sent group by origin

   Origin Sum(*)
   Email    20
   Phone   100

表 C（联系人总数）

   Origin Total
   Email   520
   Phone   300
   Social  100

【问题讨论】：

UNION ALL 查询，然后是 GROUP BY Origin 和 SUM(Total) 。

标签： sql sql-server

【解决方案1】：

您可以像这样在派生表/子查询中 union all 每个计数查询：

select 
    origin
  , Received = sum(ReceivedCount)
  , Sent     = sum(SentCount)
  , Total    = sum(ReceivedCount)+sum(SentCount)
from (
  select origin, ReceivedCount = count(*), SentCount=0
  from bd.received
  group by origin
  union all
  select origin, ReceivedCount = 0, SentCount=count(*)
  from db.sent
  group by origin
  ) s
group by origin

【讨论】：

@PaulaC 乐于助人！

【解决方案2】：

您可以使用以下查询 -

select t1.origin , sum(received) from 
(
select a.origin, count(*) received 
from db.received a 
group by a.origin 
union all
select b.origin, count(*) sent 
from db.sent b 
group by b.origin 
) as t1 
group by t1.origin

【讨论】：

【解决方案3】：

这应该可以完成工作

select origin,
       sum(count) 
from (
      select * from rec 
      union all
      select * from  sent) 
group by  
origin

这里是链接 http://www.sqlfiddle.com/#!4/0a8fc/1

【讨论】：