使用 pentaho 勺子每天更新数据库中的数据答案

【问题标题】：updating day by day data in database using pentaho spoon使用 pentaho 勺子每天更新数据库中的数据
【发布时间】：2015-03-29 07:18:53
【问题描述】：

我有一个如下所述的 SQL 查询，它将每天更新 DB 比较日期（最新的附加日期数据将在 DB 中更新），我想在使用 Pentaho 数据集成 (Kettle) 的转换中执行此操作。

Do While i < dgTest.RowCount
     dd = Mid(dgTest.Item(2, i).Value, 5, 2) & "/" & Mid(dgTest.Item(2, i).Value, 7, 2) & "/" & Mid(dgTest.Item(2, i).Value, 1, 4)

     Sql = "INSERT INTO cash ([comp], strno, bday, openread, curread,refqty,refamt, promoq," & _
          " promoa, netsprod, netsnprod, eatintc, eatins, eatouttc, eatouts, " & _
          " dttc, coffeetc, dts, coffeesales, csh, cover,recamt,crsalesamt ) Values " & _
          " ('" & dgTest.Item(0, i).Value.ToString & "','" & dgTest.Item(1, i).Value.ToString & _
          "',#" & CDate(dd) & "#,'" & dgTest.Item(3, i).Value.ToString & "'," & dgTest.Item(4, i).Value & "," & _
          dgTest.Item(5, i).Value & "," & dgTest.Item(6, i).Value & _
          "," & dgTest.Item(7, i).Value & _
          "," & dgTest.Item(8, i).Value & "," & dgTest.Item(9, i).Value & _
          "," & dgTest.Item(10, i).Value & "," & dgTest.Item(11, i).Value & _
          "," & dgTest.Item(12, i).Value & "," & dgTest.Item(13, i).Value & "," & dgTest.Item(14, i).Value & _
          "," & dgTest.Item(15, i).Value & "," & dgTest.Item(16, i).Value & "," & dgTest.Item(17, i).Value & "," & dgTest.Item(18, i).Value & "," & dgTest.Item(19, i).Value & "," & dgTest.Item(20, i).Value & "," & dgTest.Item(21, i).Value & "," & dgTest.Item(22, i).Value & ")"

      cmd = New OleDbCommand(Sql, con)
      cmd.ExecuteNonQuery()

      i = i + 1
 Loop

【问题讨论】：

标签： mysql pentaho transformation kettle data-integration

【解决方案1】：

我不明白您尝试实施的方法，但您可以做的是从输入表步骤读取数据，使用修改后的 java 脚本并指定在这个特定时间更新数据库.. 示例

    var d = new Date();
    var hour1 = d.getHours();

 if(hour1==14)
    {
        if(d.getDate()==day2 && month1==month2 && year1==year2 && hour>=13 && hour<17)
    }

【讨论】：