【发布时间】:2017-09-26 14:46:38
【问题描述】:
我正在尝试从 Spark 2.1 升级到 2.2。当我尝试读取或写入数据帧到某个位置(CSV 或 JSON)时,我收到此错误:
Illegal pattern component: XXX
java.lang.IllegalArgumentException: Illegal pattern component: XXX
at org.apache.commons.lang3.time.FastDatePrinter.parsePattern(FastDatePrinter.java:282)
at org.apache.commons.lang3.time.FastDatePrinter.init(FastDatePrinter.java:149)
at org.apache.commons.lang3.time.FastDatePrinter.<init>(FastDatePrinter.java:142)
at org.apache.commons.lang3.time.FastDateFormat.<init>(FastDateFormat.java:384)
at org.apache.commons.lang3.time.FastDateFormat.<init>(FastDateFormat.java:369)
at org.apache.commons.lang3.time.FastDateFormat$1.createInstance(FastDateFormat.java:91)
at org.apache.commons.lang3.time.FastDateFormat$1.createInstance(FastDateFormat.java:88)
at org.apache.commons.lang3.time.FormatCache.getInstance(FormatCache.java:82)
at org.apache.commons.lang3.time.FastDateFormat.getInstance(FastDateFormat.java:165)
at org.apache.spark.sql.catalyst.json.JSONOptions.<init>(JSONOptions.scala:81)
at org.apache.spark.sql.catalyst.json.JSONOptions.<init>(JSONOptions.scala:43)
at org.apache.spark.sql.execution.datasources.json.JsonFileFormat.inferSchema(JsonFileFormat.scala:53)
at org.apache.spark.sql.execution.datasources.DataSource$$anonfun$7.apply(DataSource.scala:177)
at org.apache.spark.sql.execution.datasources.DataSource$$anonfun$7.apply(DataSource.scala:177)
at scala.Option.orElse(Option.scala:289)
at org.apache.spark.sql.execution.datasources.DataSource.getOrInferFileFormatSchema(DataSource.scala:176)
at org.apache.spark.sql.execution.datasources.DataSource.resolveRelation(DataSource.scala:366)
at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:178)
at org.apache.spark.sql.DataFrameReader.json(DataFrameReader.scala:333)
at org.apache.spark.sql.DataFrameReader.json(DataFrameReader.scala:279)
我没有为 dateFormat 设置默认值,所以我不明白它的来源。
spark.createDataFrame(objects.map((o) => MyObject(t.source, t.table, o.partition, o.offset, d)))
.coalesce(1)
.write
.mode(SaveMode.Append)
.partitionBy("source", "table")
.json(path)
我仍然得到这个错误:
import org.apache.spark.sql.{SaveMode, SparkSession}
val spark = SparkSession.builder.appName("Spark2.2Test").master("local").getOrCreate()
import spark.implicits._
val agesRows = List(Person("alice", 35), Person("bob", 10), Person("jill", 24))
val df = spark.createDataFrame(agesRows).toDF();
df.printSchema
df.show
df.write.mode(SaveMode.Overwrite).csv("my.csv")
这是架构: 根 |-- 名称:字符串(可为空 = true) |-- 年龄: long (nullable = false)
【问题讨论】:
-
我看不出你的代码有什么问题。你能分享一下 MyObject 类的定义吗?尝试手动将对象转换为 json,然后尝试另存为字符串
-
case class MyObject(source: String, table: String, partition: Int, offset: Long, updatedOn: String)
-
以字符串形式读取和写入日期字段。使用 SimpleDateFormat 手动操作日期字段
标签: scala apache-spark spark-dataframe