【问题标题】:Why is failing Pyspark when running an pandas_udf?为什么运行 pandas_udf 时 Pyspark 失败?
【发布时间】:2019-08-08 12:43:26
【问题描述】:

在 PySpark 中运行 pandas UDF 时出现此错误。这是使用外部库textdistance的UDF:

def algoritmos_comparacion(num_serie_rec, num_serie_exp):
    d = textdistance.hamming(num_serie_rec, num_serie_exp)
    return str(d)

然后我注册函数:

algoritmos_comparacion_udf = f.pandas_udf(algoritmos_comparacion, StringType())

最后我使用了这个 udf:

df.withColumn("hamming", algoritmos_comparacion_udf(f.col("num_serie_exp"), f.col("num_serie_rec")))

我已经安装了 pandas 和 pyarrow 0.8.0 版。我收到此错误:

TypeError: 'Series' objects are mutable, thus they cannot be hashed

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "/DATOS/var/log/hadoop/yarn/local/usercache/bguser/appcache/application_1563894657824_0447/container_e66_1563894657824_0447_01_000002/pyspark.zip/pyspark/worker.py", line 235, in main
    process()
  File "/DATOS/var/log/hadoop/yarn/local/usercache/bguser/appcache/application_1563894657824_0447/container_e66_1563894657824_0447_01_000002/pyspark.zip/pyspark/worker.py", line 230, in process
    serializer.dump_stream(func(split_index, iterator), outfile)
  File "/DATOS/var/log/hadoop/yarn/local/usercache/bguser/appcache/application_1563894657824_0447/container_e66_1563894657824_0447_01_000002/pyspark.zip/pyspark/serializers.py", line 267, in dump_stream
    for series in iterator:
  File "<string>", line 1, in <lambda>
  File "/DATOS/var/log/hadoop/yarn/local/usercache/bguser/appcache/application_1563894657824_0447/container_e66_1563894657824_0447_01_000002/pyspark.zip/pyspark/worker.py", line 92, in <lambda>
    return lambda *a: (verify_result_length(*a), arrow_return_type)
  File "/DATOS/var/log/hadoop/yarn/local/usercache/bguser/appcache/application_1563894657824_0447/container_e66_1563894657824_0447_01_000002/pyspark.zip/pyspark/worker.py", line 83, in verify_result_length
    result = f(*a)
  File "/DATOS/var/log/hadoop/yarn/local/usercache/bguser/appcache/application_1563894657824_0447/container_e66_1563894657824_0447_01_000002/pyspark.zip/pyspark/util.py", line 55, in wrapper
    return f(*args, **kwargs)
  File "/home/bguser/SII-IVA/jobs/caso3/caso3.py", line 39, in algoritmos_comparacion
  File "/DATOS/var/log/hadoop/yarn/local/usercache/bguser/appcache/application_1563894657824_0447/container_e66_1563894657824_0447_01_000002/virtualenv_application_1563894657824_0447_0/lib/python3.6/site-packages/textdistance/algorithms/edit_based.py", line 49, in __call__
    result = self.quick_answer(*sequences)
  File "/DATOS/var/log/hadoop/yarn/local/usercache/bguser/appcache/application_1563894657824_0447/container_e66_1563894657824_0447_01_000002/virtualenv_application_1563894657824_0447_0/lib/python3.6/site-packages/textdistance/algorithms/base.py", line 91, in quick_answer
    if self._ident(*sequences):
  File "/DATOS/var/log/hadoop/yarn/local/usercache/bguser/appcache/application_1563894657824_0447/container_e66_1563894657824_0447_01_000002/virtualenv_application_1563894657824_0447_0/lib/python3.6/site-packages/textdistance/algorithms/base.py", line 110, in _ident
    if e1 != e2:
  File "/DATOS/var/log/hadoop/yarn/local/usercache/bguser/appcache/application_1563894657824_0447/container_e66_1563894657824_0447_01_000002/virtualenv_application_1563894657824_0447_0/lib/python3.6/site-packages/pandas/core/generic.py", line 1556, in __nonzero__
    self.__class__.__name__
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

我该如何解决这个错误?

要重现它,您可以使用库 textdistance 的任何算法运行 pandas_udf。例如:

import textdistance
import pyspark.sql.functions as f

def algoritmos_comparacion(num_serie_rec, num_serie_exp):
    data = {}
    algoritmos = {
        "hamming":textdistance.hamming,
        "levenshtein":textdistance.levenshtein,
        "damerau_levenshtein":textdistance.damerau_levenshtein,
        "jaro":textdistance.jaro,
        "mlipns":textdistance.mlipns,
        "strcmp95":textdistance.strcmp95,
        "needleman_wunsch":textdistance.needleman_wunsch,
        "gotoh":textdistance.gotoh,
        "smith_waterman":textdistance.smith_waterman
    }
    for name, alg in algoritmos.items():
        try:
            data[name] = str(alg(num_serie_rec, num_serie_exp))
        except:
            data[name] = "ERROR"
    return data

algoritmos_comparacion_udf=f.pandas_udf(algoritmos_comparacion,MapType(StringType(),StringType()))

dataframe.withColumn("algorithms", algoritmos_comparacion_udf(f.col("a"), f.col("b")))

谢谢。

【问题讨论】:

  • 您是否通过 col("num_serie_exp") 和 col("num_serie_rec") 传递可迭代对象?
  • @mazaneicha 不重复,因为我不使用任何布尔运算符。
  • 你能创建一个 MVCE 吗?在这种情况下会更容易为您提供帮助。
  • @johnckane 是的,在带有 lambda 的 pandas udf 中使用函数 apply 和 python 函数。 func_udf = f.pandas_udf(lambda s: s.apply(func))

标签: pandas apache-spark pyspark pyarrow


【解决方案1】:

解决了这个问题:

algoritmos_comparacion_udf=f.pandas_udf(lambda s: s.apply(algoritmos_comparacion),MapType(StringType(),StringType()))

dataframe.withColumn("algorithms", algoritmos_comparacion_udf(f.col("a"), f.col("b")))

【讨论】:

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