【发布时间】:2016-11-07 14:21:38
【问题描述】:
我想从现有数据框(在连接后创建)中选择多个列,并希望将这些文件排序为我的目标表结构。如何做呢 ?我使用的方法如下。在这里,我可以选择需要但无法按顺序制作的必要列。
Required (Target Table structure) :
hist_columns = ("acct_nbr","account_sk_id", "zip_code","primary_state", "eff_start_date" ,"eff_end_date","eff_flag")
account_sk_df = hist_process_df.join(broadcast(df_sk_lkp) ,'acct_nbr','inner' )
account_sk_df_ld = account_sk_df.select([c for c in account_sk_df.columns if c in hist_columns])
>>> account_sk_df
DataFrame[acct_nbr: string, primary_state: string, zip_code: string, eff_start_date: string, eff_end_date: string, eff_flag: string, hash_sk_id: string, account_sk_id: int]
>>> account_sk_df_ld
DataFrame[acct_nbr: string, primary_state: string, zip_code: string, eff_start_date: string, eff_end_date: string, eff_flag: string, account_sk_id: int]
account_sk_id 需要在第二位。最好的方法是什么?
【问题讨论】:
标签: python apache-spark pyspark apache-spark-sql