oracle SQL select from this date_id to this date_id

Question

我必须显示 2011-2014 年表格中的数据。该表具有另一个名为 time 的表的时间 ID，该表存储实际年份。 我有从这个日期 ID 到日期 ID 中选择数据的声明。

SELECT sum(no_of_placements)
  FROM fact_accounts
 WHERE
  (SELECT account_dim.account_id FROM account_dim WHERE account_dim.account_name = 'DCompany1')
     = fact_accounts.fk2
  AND (
       (SELECT time_dim.time_id FROM time_dim WHERE time_dim.year = 2011)
          = fact_accounts.fk1_time_id
    OR (SELECT time_dim.time_id FROM time_dim WHERE time_dim.year = 2012)
          = fact_accounts.fk1_time_id
    OR (SELECT time_dim.time_id FROM time_dim WHERE time_dim.year = 2013)
          = fact_accounts.fk1_time_id
    OR (SELECT time_dim.time_id FROM time_dim WHERE time_dim.year = 2014)
          = fact_accounts.fk1_time_id
  )
GROUP BY fact_accounts.no_of_placements

如何在不设置条件以匹配 time_id 的情况下实现相同的目标？如果年份范围较大，这似乎无效。

Answer 1

SELECT sum(no_of_placements)
FROM fact_accounts, account_dim, time_dim 
WHERE account_dim.account_id = fact_accounts.fk2
AND account_dim.account_name = 'DCompany1'  
AND fact_accounts.FK1_TIME_ID = time_dim.time_id
AND time_dim.year BETWEEN 2011 AND 2014

GROUP BY fact_accounts.no_of_placements

或

SELECT sum(no_of_placements)
    FROM fact_accounts,  
    WHERE
    (select account_dim.account_id FROM account_dim WHERE account_dim.account_name = 'DCompany1') = fact_accounts.fk2

AND fact_accounts.FK1_TIME_ID IN
(select time_dim.time_id from time_dim WHERE 
time_dim.year BETWEEN 2011 AND 2014)

GROUP BY fact_accounts.no_of_placements

但是为什么你们既要按 no_of_placements 求和又要按 no_of_placements 分组呢？这对我来说毫无意义。