SQL Row_Number() 不排序日期

Question

我有一个查询，我试图从我的ROW_NUMBER() 选择中获取最近的日期。我在ORDER BY 子句中尝试了MAX() 和DESC。它不会将最近的日期显示为RowNum 1。

这是我的查询：

;WITH cte3 AS
(       
    SELECT
        o.PartNo, 
        o.JobNo,
        MAX(tt.TicketDate) as rawr,
        ROW_NUMBER() OVER (PARTITION BY o.JobNo, o.PartNo 
                           ORDER BY tt.TicketDate DESC) as RowNum    
    FROM
        OrderDet AS o    
    INNER JOIN 
        TimeTicketDet AS tt ON o.JobNo = tt.JobNo       
    WHERE
        o.Status = 'Open'
    GROUP BY
        tt.TicketDate, o.JobNo, o.PartNo
)    
SELECT *
FROM cte3

当我得到它给我正确的结果时，我会在 cte 查询中添加一个WHERE RowNum = 1。

根据我当前的查询，结果如下：

+--------+-------+-----------+--------+
| PartNo | JobNo |   rawr    | RowNum |
+--------+-------+-----------+--------+
|   1234 |    20 | 5/30/2012 |      1 |
|   1234 |    20 | 5/29/2012 |      2 |
|   1234 |    20 | 5/25/2012 |      3 |
|   1234 |    20 | 5/24/2012 |      4 |
|   1234 |    20 | 5/23/2012 |      5 |
|   1234 |    20 | 5/22/2012 |      6 |
|   1234 |    20 | 5/16/2012 |      7 |
|   1234 |    20 | 5/15/2012 |      8 |
|   1234 |    20 | 5/14/2012 |      9 |
|   1234 |    20 | 5/11/2012 |     10 |
|   1234 |    20 | 5/10/2012 |     11 |
|   1234 |    20 | 5/9/2012  |     12 |
|   1234 |    20 | 3/27/2015 |     13 |
|   1234 |    20 | 1/3/2013  |     14 |
|   1234 |    20 | 1/2/2013  |     15 |
+--------+-------+-----------+--------+

RowNum = 13 是最近的日期。我是在错误地组织排序还是错误地转换了日期？

编辑：

TimeTicketDet 表示例数据：

+------------+-------+
| TicketDate | JobNo |
+------------+-------+
| 5/9/2012   |    20 |
| 5/10/2012  |    20 |
| 5/24/2012  |    20 |
| 3/27/2015  |    20 |
| 5/22/2012  |    20 |
| 5/10/2012  |    20 |
| 5/11/2012  |    20 |
| 5/9/2012   |   100 |
| 5/10/2012  |   100 |
| 5/24/2012  |   100 |
| 3/27/2015  |   100 |
| 5/22/2012  |   100 |
| 5/10/2012  |   100 |
| 5/11/2012  |   100 |
+------------+-------+

OrderDet 表示例数据：

+--------+--------+-------+
| PartNo | Status | JobNo |
+--------+--------+-------+
|   1234 | Open   |    20 |
|   1234 | Open   |   100 |
+--------+--------+-------+

期望的结果：

+--------+------------+-------+--------+
| PartNo | TicketDate | JobNo | RowNum |
+--------+------------+-------+--------+
|   1234 | 3/27/2015  |    20 |      1 |
|   1234 | 3/27/2015  |   100 |      1 |
+--------+------------+-------+--------+

Answer 1

正如我在my comment 中提到的，由于您的TicketDate 列是一个字符，您需要将convert it 转换为datetime 以便按实际日期对其进行排序。现在，您正在按不正确的字符串值对其进行排序。

我建议您将查询更改为以下内容：

;WITH cte3 AS
(       
    SELECT
        o.PartNo, 
        o.JobNo,
        MAX(tt.TicketDate) as rawr,
        ROW_NUMBER() OVER (PARTITION BY o.JobNo, o.PartNo 
                           ORDER BY cast(tt.TicketDate as datetime) DESC) as RowNum    
    FROM
        OrderDet AS o    
    INNER JOIN 
        TimeTicketDet AS tt ON o.JobNo = tt.JobNo       
    WHERE
        o.Status = 'Open'
    GROUP BY
        cast(tt.TicketDate as datetime), o.JobNo, o.PartNo
)    
SELECT *
FROM cte3
where RowNum = 1;

这是demo。通过将char 转换为row_number 中的datetime，您将按日期而不是字符串对数据进行排序。

此外，您实际上并不需要 max() 和 GROUP BY，因为通过将 TicketDate 转换为日期时间，您将返回正确的行：

;WITH cte3 AS
(       
    SELECT
        o.PartNo, 
        o.JobNo,
        tt.TicketDate as rawr,
        ROW_NUMBER() OVER (PARTITION BY o.JobNo, o.PartNo 
                           ORDER BY cast(tt.TicketDate as datetime) DESC) as RowNum    
    FROM
        #OrderDet AS o    
    INNER JOIN 
        #TimeTicketDet AS tt ON o.JobNo = tt.JobNo       
    WHERE
        o.Status = 'Open'
)    
SELECT *
FROM cte3
where RowNum =1;

Answer 2

正如 Ollie 建议的那样，您可以将您的字符串 CAST DATETIME 并且您不需要额外的 Group By

SQL DEMO

;WITH cte3 AS
(       
    SELECT
        o.PartNo, 
        o.JobNo,
        tt.TicketDate as rawr,
        ROW_NUMBER() OVER (PARTITION BY o.JobNo, o.PartNo 
                           ORDER BY cast(tt.TicketDate as datetime) DESC) as RowNum    
    FROM  OrderDet AS o    
    JOIN  TimeTicketDet AS tt 
      ON o.JobNo = tt.JobNo       
    WHERE
        o.Status = 'Open'
)    
SELECT *
FROM cte3
WHERE RowNum = 1

输出