如果三个表的ConditionID 相同,您应该可以使用Multiple Table Delete Syntax:
DELETE Table1, Table2, Table3
FROM Table1
JOIN Table2 ON (Table2.ConditionID = Table1.ConditionID)
JOIN Table3 ON (Table3.ConditionID = Table2.ConditionID)
WHERE Table1.ConditionID = ?;
测试用例:
CREATE TABLE Table1 (id int, ConditionID int);
CREATE TABLE Table2 (id int, ConditionID int);
CREATE TABLE Table3 (id int, ConditionID int);
INSERT INTO Table1 VALUES (1, 100);
INSERT INTO Table1 VALUES (2, 100);
INSERT INTO Table1 VALUES (3, 200);
INSERT INTO Table2 VALUES (1, 100);
INSERT INTO Table2 VALUES (2, 200);
INSERT INTO Table2 VALUES (3, 300);
INSERT INTO Table3 VALUES (1, 100);
INSERT INTO Table3 VALUES (2, 100);
INSERT INTO Table3 VALUES (3, 100);
结果:
DELETE Table1, Table2, Table3
FROM Table1
JOIN Table2 ON (Table2.ConditionID = Table1.ConditionID)
JOIN Table3 ON (Table3.ConditionID = Table2.ConditionID)
WHERE Table1.ConditionID = 100;
SELECT * FROM Table1;
+------+-------------+
| id | ConditionID |
+------+-------------+
| 3 | 200 |
+------+-------------+
1 row in set (0.00 sec)
SELECT * FROM Table2;
+------+-------------+
| id | ConditionID |
+------+-------------+
| 2 | 200 |
| 3 | 300 |
+------+-------------+
2 rows in set (0.00 sec)
SELECT * FROM Table3;
Empty set (0.00 sec)