用于过滤两个子实体的 Spring Boot 规范答案

【问题标题】：Spring boot Specification to filter on two child entities用于过滤两个子实体的 Spring Boot 规范
【发布时间】：2020-03-10 11:29:54
【问题描述】：

存在名称为Transaction 的实体，它有两个名称为ServiceTransaction 和OtherFeeTransaction 的映射(@OneToOne) 子实体。能够使用规范对所有字段进行过滤，但同时对子实体字段进行过滤。

交易实体：

 public class Transaction implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(generator = "UUID")
    @GenericGenerator(
        name = "UUID",
        strategy = "org.hibernate.id.UUIDGenerator"
    )
    @Column(name = "id", updatable = false, nullable = false, columnDefinition = "uuid")
    private UUID id;

    @Column(name = "txn_id")
    private String txnId;

    @Column(name = "account_no")
    private String accountNo;

    @Column(name = "date", nullable = false)
    private Date date;

    @OneToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    @JoinColumn(name = "service_id")
    private ServiceTransaction serviceTransaction;

    @OneToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    @JoinColumn(name = "other_id")
    private OtherFeeTransaction otherFeeTransaction;

    }

其他费用实体：

public class OtherFeeTransaction implements Serializable {

private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(generator = "UUID")
@GenericGenerator(
    name = "UUID",
    strategy = "org.hibernate.id.UUIDGenerator"
)
@Column(name = "id", updatable = false, nullable = false, columnDefinition = "uuid")
private UUID id;

@Column(name = "other_fee_id")
private UUID otherFeeId;

@Column(name = "type_data_id")
private String typeDataId;

}

服务实体：

public class ServiceTransaction implements Serializable {

private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(generator = "UUID")
@GenericGenerator(
    name = "UUID",
    strategy = "org.hibernate.id.UUIDGenerator"
)
@Column(name = "id", updatable = false, nullable = false, columnDefinition = "uuid")
private UUID id;

@Column(name = "parcel_id")
private String cadastreId;

@Column(name = "ba_unit_id")
private String titleId;

}

规格

Predicate service = cb.like(root.<ServiceTransaction>get("serviceTransaction").get("titleId"),
                "%" + criteria.getTitleId() + "%");

Predicate other = cb.like(root.<OtherFeeTransaction>get("otherFeeTransaction").get("typeDataId"),
                "%" + criteria.getTitleId() + "%");
//works if any one of the predicates is added, but doesn't work if both given like below
predicateList.add(service);
predicateList.add(other);

criteriaQuery.where(cb.and(predicateList.toArray(new Predicate[predicateList.size()])))
            .getRestriction();

如果predicate 的service 或other 中的任何一个被给出，则能够得到结果，但如果同时给出predicates，则不能。

即使尝试使用 or caluse 它也不起作用

【问题讨论】：

请添加实体。
添加了实体
究竟是什么问题/
我不知道你的标准是什么。但是您应该先尝试查询数据库。可能没有符合条件的数据。
另外，你用“criteria.getTitleId()”创建了两个谓词，对吗？

标签： hibernate spring-boot spring-data-jpa predicate criteriaquery

【解决方案1】：

我成功了，忘记在映射的实体上使用 LeftJoin

   Predicate service = cb.like(root.join("serviceTransaction",JoinType.LEFT).get("cadastreId"),
            "%" + criteria.getParcelId() + "%");

        Predicate other = cb.like(root.join("otherFeeTransaction",JoinType.LEFT).get("typeDataId"),
            "%" + criteria.getParcelId() + "%");

        predicateList.add(cb.or(service,other));

【讨论】：