【发布时间】：2020-04-05 15:17:24
【问题描述】：
我刚刚学会了如何使用 Repository Java 进行 Pageable（我有一个 BBDD MySQL）。我基本上将 DAO 与我的模型 (pregunta) 一起使用，并将我的模型投射到我的 DTO (preguntaDTO)。
public Page<PreguntaDTO> getAllPreguntasPorPagina(Pageable pageable){
return preguntaRepository.findAll(pageable).map(PreguntaDTO::fromEntity);
}
我的控制器接收分页参数。
@GetMapping("/listadoPreguntasPaginadas")
public ResponseEntity<Page<PreguntaDTO>> listadoPreguntasPaginadas(
@RequestParam(defaultValue = "0") int page,
@RequestParam(defaultValue = "10") int size,
@RequestParam(defaultValue = "pregunta") String order,
@RequestParam(defaultValue = "true") boolean asc
) {
Page<PreguntaDTO> preguntaDTOpaginada= preguntaService.listadoPreguntasPageables(PageRequest.of(page, size, Sort.by(order)));
return new ResponseEntity<Page<PreguntaDTO>>(preguntaDTOpaginada, HttpStatus.OK);
}
但是现在，我需要在我的 JQUERY (text and id) 中使用参数。我会尝试更好地解释它。 我的模型是：
@Entity
@Table (name="preguntas")
@EntityListeners(AuditingEntityListener.class) // sin esto no genera fecha automatica
@Getter
@Setter
public class Pregunta implements Serializable {
private static final long serialVersionUID = 5191280932150590610L;
@Id // definimos clave primaria
@GeneratedValue(strategy=GenerationType.AUTO) // que se genere de forma automatica y crezca
private Long id;
@Temporal(TemporalType.TIMESTAMP)
@LastModifiedDate
private Date createAt;
@NotBlank // que no este campo en blanco, validar documento
@NotNull(message = "Nombre no puede ser nulo")
private String pregunta;
private Boolean activa=true;
private Long deEnfermedadById;//ID de Enfermedad
private Long createdById;//ID de usuario
private Boolean denunciado=false;
private String aux="Campo auxiliar sin usar";
}
我的搜索，除了可分页之外，还必须返回我所有的问题（pregunta）：
- 在字段 deEnfermedadById 中带有一个 id (deEnfermedadById :number) 并且，
- pregunta (type, pregunta:string) 字段中的文本 (cadena: string)
我知道如何使用实体管理查找那种列表，但在这里我不知道你使用可分页。
您可以在上面看到我是如何做到的。
public List<Pregunta> listadoPreguntasByIdEnfermedad(Long idEnf, String cadena) {
List<Pregunta> lista = new ArrayList<>();
String sql = "select * from sanihelp.preguntas where "
+ "de_enfermedad_by_id = ?";
if (cadena != null) {
sql = sql.concat(" and pregunta like ? ");
};
try {
Query query = em.createNativeQuery(sql);
int indice=1;
query.setParameter(indice , idEnf);
if (cadena != null) {
query.setParameter(++indice, "%" + cadena + "%");
}
for (Object o : query.getResultList()) {
Object[] objeto = (Object[]) o;
Pregunta modelo = new Pregunta();
modelo.setId(((BigInteger) objeto[0]).longValue()); modelo.setActiva(Boolean.getBoolean(String.valueOf(objeto[1])));
modelo.setAux(String.valueOf(objeto[2]));
modelo.setCreateAt((java.util.Date)objeto[3]);
modelo.setCreatedById(((BigInteger) objeto[4]).longValue());
modelo.setDeEnfermedadById(((BigInteger) objeto[5]).longValue()); modelo.setDenunciado(Boolean.getBoolean(String.valueOf(objeto[6])));
modelo.setPregunta(String.valueOf(objeto[7]));
lista.add(modelo);
}
} catch (Exception e) {
System.out.println("excepcion lanzada" + e);
}
return lista;
}
你怎么看，我有点卡住了。使用实体管理我无法进行分页，而使用 Repository Java 我不知道如何向我的可分页方法添加一些参数（id 和 text）
感谢您的帮助。
:-)
以上界面的一些额外信息。
package com.uned.project.sanitaUned.repository;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.stereotype.Repository;
import com.uned.project.sanitaUned.model.Pregunta;
@Repository
public interface PreguntaRepository extends JpaRepository<Pregunta, Long> {
}
延伸到：
*/
@NoRepositoryBean
public interface JpaRepository<T, ID> extends PagingAndSortingRepository<T, ID>, QueryByExampleExecutor<T> {
以及可分页的扩展
@NoRepositoryBean
public interface PagingAndSortingRepository<T, ID> extends CrudRepository<T, ID> {
/**
* Returns all entities sorted by the given options.
*
* @param sort
* @return all entities sorted by the given options
*/
Iterable<T> findAll(Sort sort);
/**
* Returns a {@link Page} of entities meeting the paging restriction provided in the {@code Pageable} object.
*
* @param pageable
* @return a page of entities
*/
Page<T> findAll(Pageable pageable);
}
我试过了：
@Repository
public interface PreguntaRepository extends JpaRepository<Pregunta, Long> {
/* */
@Query ("select * from sanihelp.preguntas where de_enfermedad_by_id = :de_enfermedad_by_id")
Page <Pregunta> findAllWithFields(Pageable pageable , @Param ("de_enfermedad_by_id") long de_enfermedad_by_id );
}
但它不起作用，当我开始出现下一个错误时，它在服务器中失败了。
Error starting ApplicationContext. To display the conditions report re-run your application with 'debug' enabled.
2020-04-07 18:16:44.091 ERROR 8424 --- [ restartedMain] o.s.boot.SpringApplication : Application run failed
org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'preguntaController': Unsatisfied dependency expressed through field 'preguntaService'; nested exception is org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'preguntaService': Unsatisfied dependency expressed through field 'preguntaDAO'; nested exception is org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'preguntaDAO': Unsatisfied dependency expressed through field 'preguntaRepository'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'preguntaRepository': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Validation failed for query for method public abstract org.springframework.data.domain.Page com.uned.project.sanitaUned.repository.PreguntaRepository.findAllWithFields(org.springframework.data.domain.Pageable,long)!
at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:596) ~[spring-beans-5.1.9.RELEASE.jar:5.1.9.RELEASE]
at org.springframework.beans.factory.annotation.InjectionMetadata.inject(InjectionMetadata.java:90) ~[spring-beans-5.1.9.RELEASE.jar:5.1.9.RELEASE]
【问题讨论】：
标签： java jquery spring hibernate pageable