使用“，”从数据库中提取数据到 csv 文件

Question

这是我从数据库中提取数据到 csv 文件的代码。它工作正常，但现在我把它放在数据有地址的程序中，因此有逗号（，），我在打印它时遇到问题。

看起来是这样的：

Name        Address1         Address2         City          Email
Name1       123 Mcarthur     San Juan City    12 Jones      Manila

应该是这样的：

Name        Address1                       Address2         City          Email     
Name1    123 Mcarthur, San Juan City   12 Jones, Manila     Manila      sample@yahoo.com

城市和电子邮件被推送到另一列。我搜索了互联网，但我看到的只是用逗号 (, ) 导入的数据。

另外，php 中的警告和错误消息也会导出到 csv 文件中。我没有那么大的问题，因为一旦我解决了这个问题，我认为不会有任何警告。

那么这是我的代码：

        if(isset($_POST['csvextract'])){
        $name = "sample";
        $file = $name.".csv";

            $con = mysql_connect("localhost", "root");
            if(!$con){
                 echo "Error connection";
                     }

             $select_db = mysql_select_db('outbound', $con);
             if(!$select_db){
                 echo "Error to select database";
                    }
            mysql_set_charset("utf8", $con);

             header("Content-type: text/csv; charset=UTF-8");
             header('Content-disposition: attachment; filename='.basename($file)); 

           $myquery = mysql_query("SELECT * FROM temp");

        //While loop to fetch the records
        $contents = "Name, Company, Address1, Address2, City, Province, Postal Code, Contact No, Email, Commodity, Type, Weight, Length, Width, Height, Decreased Value, Special Instruction, Shipping Reference, Payment Method, Package No, Tracking No\n";
        while($row = mysql_fetch_array($myquery))
        {
            $contents.=$row['0'].",";
            $contents.=$row['1'].",";
            $contents.=$row['2'].",";
            $contents.=$row['3'].",";
            $contents.=$row['4'].",";
            $contents.=$row['5'].",";
            $contents.=$row['6'].",";
            $contents.=$row['7'].",";
            $contents.=$row['8'].",";
            $contents.=$row['9'].",";
            $contents.=$row['10'].",";
            $contents.=$row['11'].",";
            $contents.=$row['12'].",";
            $contents.=$row['13'].",";
            $contents.=$row['14'].",";
            $contents.=$row['15'].",";
            $contents.=$row['16'].",";
            $contents.=$row['17'].",";
            $contents.=$row['18'].",";
            $contents.=$row['19'].",";
            $contents.=$row['20'].",";
            $contents.=$row['21']."\n"; 
        }

        $contents_final = chr(255).chr(254).mb_convert_encoding($contents, "UTF-16LE","UTF-8");
        print $contents_final;
        }

Answer 1

我不确定你是否已经在使用它。但我对你的代码做了一点改动。

代码如下：

if (isset($_POST['csvextract'])) {
$name = "sample";
$file = $name . ".csv";
$delimiter = ',';

$con = mysql_connect("localhost", "root");
if (!$con) {
    echo "Error connection";
    exit;
}

$select_db = mysql_select_db('outbound', $con);
if (!$select_db) {
    echo "Error to select database";
    exit;
}
mysql_set_charset("utf8", $con);

header("Content-type: text/csv; charset=UTF-8");
header('Content-disposition: attachment; filename=' . basename($file));

$myquery = mysql_query("SELECT * FROM temp");

//While loop to fetch the records
$contents = "Name, Company, Address1, Address2, City, Province, Postal Code, Contact No, Email, Commodity, Type, Weight, Length, Width, Height, Decreased Value, Special Instruction, Shipping Reference, Payment Method, Package No, Tracking No\n";
while ($row = mysql_fetch_array($myquery)) {

    for ($i = 0; $i < 22; $i++) {
        if (false === strpos($row[$i], $delimiter)) {
            $contents .= '"' . $row[$i] . '"';
        } else {
            $contents.=$row[$i];
        }
        if ($i === 21) {
            $contents .= "\n";
        } else {
            $contents .= $delimiter;
        }
    }
}

$contents_final = chr(255) . chr(254) . mb_convert_encoding($contents, "UTF-16LE", "UTF-8");
print $contents_final;
}

我改成关注了。

1. 我在脚本顶部添加了一个分隔符变量。这样，您可以在分隔符之间轻松切换，所以如果它从 , 变为 ;您只需编辑 1 行即可。
2. 我使用了 for 循环而不是所有行，因为每个表都只是一个数字。
3. 添加检查以查看字符串中是否包含分隔符，如果是，请在其周围放置 qoutes
4. 检查$i 是否为 21，因为那我们需要换行。
5. 在没有db连接或无法选择数据库时添加退出

如果这不起作用，请告诉我，我会修复它。请注意，我自己没有尝试过此代码。

Answer 2

使用这个：

echo "Name, Company, Address1, Address2, City, Province, Postal Code, Contact No, Email, Commodity, Type, Weight, Length, Width, Height, Decreased Value, Special Instruction, Shipping Reference, Payment Method, Package No, Tracking No\n";
while ($row = mysql_fetch_row($myquery)) {
    fputcsv(STDOUT, $row);
}