【问题标题】:Help with a multilevel menu with json and jquery帮助使用 json 和 jquery 的多级菜单
【发布时间】:2011-08-26 01:04:57
【问题描述】:

我正在尝试制作一个在单击“>”时会滑动的多级菜单。第一个问题是 CSS 工作不正常,

    没有向左浮动。

    我需要的是只显示一个ul,如果单击“>”显示“儿童”菜单滑动或显示它,任何方法都是有用的。

    准备测试的完整代码是here

    我正在尝试这样做:menu

    JavaScript

$(document).ready(function(){
    var json = [{"id":"1","parent":"0","slug":"digitalart","name":"Digital Art"},{"id":"2","parent":"1","slug":"3d","name":"3-Dimensional Art"},{"id":"39","parent":"1","slug":"drawings","name":"Drawings"},{"id":"3","parent":"2","slug":"abstract","name":"Abstract"},{"id":"4","parent":"2","slug":"characters","name":"Characters"},{"id":"12","parent":"2","slug":"objects","name":"Objects"},{"id":"23","parent":"2","slug":"scenes","name":"Scenes"},{"id":"32","parent":"2","slug":"unsorted","name":"Unsorted"},{"id":"33","parent":"2","slug":"vehicles","name":"Vehicles"},{"id":"5","parent":"4","slug":"creatures","name":"Animals & Creatures"},{"id":"6","parent":"4","slug":"cartoon","name":"Cartoon"},{"id":"7","parent":"4","slug":"female","name":"Female"},{"id":"8","parent":"4","slug":"groups","name":"Groups"},{"id":"9","parent":"4","slug":"machines","name":"Machines & Robots"},{"id":"10","parent":"4","slug":"male","name":"Male"},{"id":"11","parent":"4","slug":"misc","name":"Miscellaneus"}];
    build_menu(json, 0);
});

function build_menu(json, parent){
    var menu;
    var item = "";
    var counter = 0;
    if(parent != '0'){
        item += '<li><a class="more" onClick="show(); return false;" href="#">Back</a></li>';
    }
    $.each(json, function(i, category) {
        if(category.parent == parent){
            var more = '<a class="more" onClick="show('+parent+'); return false;" href="#">></a>';

            item = item + '<li>' + category.name + more + '</li>';
            build_menu(json, category.id);
            counter++;
        }
    });

    if(counter > 0){    
        menu = '<ul class="menu" id="category' + parent + '">' + item + '</ul>';
        $('#menu').prepend(menu);
    }
}

function show(id){
    $(".menu").hide();
    $("#category"+id).show();
}

css

#menu{
    width: 180px;
    overflow: hidden;
}

#menu ul{
    width: 180px;
    float: left;
    list-style: none;
}

#menu ul li{
    border: solid 1px black;
    margin-bottom: 5px;
}

#menu li .more{
    //float: right;
    text-decoration: none;
    margin-right: 5px;
}

html

<div id="menu">
</div>

【问题讨论】:

  • 菜单有什么问题?它适用于您的示例。您所说的“'s 没有向左浮动”是什么意思
  • @SeinOxygen 你的赏金已经得到满足 :-)
  • @SeinOxygen 你的赏金已经得到满足
  • 这里列出的所有 jsfiddle 链接似乎都已过期....有人可以再补一下吗...

标签: jquery css json menu multi-level


【解决方案1】:

解决了。

使用 jQuery:

build_menu(json, 0);
    $('.back').hide();
    $('ul').not('.parent').hide();
});

function build_menu(json, parent, parentID) {
    var menu, li;
    var item = $('<ul class="menu ' + (parent == '0' ? 'parent' : '') + '" id="category' + parent + '"></ul>');
    var counter = 0;
    if (parent != '0') {
        li = $('<li><a class="back" href="#">Back</a></li>');
        li.click(function() {
            $('.back').hide();
            $("#category" + parentID).show();
            $("#category" + parent).hide();
            $('.back', $("#category" + parentID)).show();
            return false;
        })

        li.appendTo(item);
    }
    $.each(json, function(i, category) {
        if (category.parent == parent) {
            var more = $('<a class="more" href="#">></a>');
            more.click(function(e) {
                e.preventDefault();
                $('.back', $("#category" + category.id)).show();
                $("#category" + category.id).show();
                $("#category" + parent).hide();
                console.log("#category" + category.id, $("#category" + category.id));
                if ($("#category" + category.id).length <= 0) { //NO CHILDREN
                    $('.back').hide();
                    $("#category" + parent).show();
                    $('.back', $("#category" + parent)).show();
                }
                return false;
            })
            li = $('<li>' + category.name + '</li>');
            more.appendTo(li);
            li.appendTo(item);
            build_menu(json, category.id, parent);
            counter++;
        }
    });

    if (counter > 0) {
        menu = item;
        $('#menu').prepend(menu);
    }
}

小提琴:http://jsfiddle.net/maniator/CxBrW/25/
摆弄幻灯片动画:http://jsfiddle.net/maniator/CxBrW/26/

更新

如果没有孩子,这里是没有胡萝卜的小提琴:http://jsfiddle.net/maniator/CxBrW/36/

【讨论】:

  • @Neal 一切?如果我在数字绘图上单击 >,它必须显示“3 维艺术”和“绘图”,如果我单击“3 维艺术”,它应该显示“抽象”、“字符”、“对象”...
  • @Blaya,当菜单没有更多子项时,我停止了菜单
  • @Neal,完美!如果您可以在类别没有儿童时隐藏“>”链接,您将获得所有积分:P
  • @Blaya,这可能不太容易,几分钟
  • @Neal 我注意到如果我使用 build_menu(json, 1);它不会生成显示子项和返回链接的菜单。
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