【发布时间】:2014-09-13 10:41:12
【问题描述】:
我有这个 sql 查询:
select
rooms.*,
COUNT(DISTINCT(o.resident_id)) as resident_count,
COUNT(reviews.id) as review_count,
COUNT(photos.id) as photo_count,
AVG(reviews.rating) as mean_review
from
t_rooms rooms
JOIN
t_room_listings listings on listings.room_id = rooms.id
JOIN
t_occupancies o on o.listing_id = listings.id
LEFT JOIN
t_reviews reviews on reviews.occupancy_id = o.id
LEFT JOIN
t_photos photos on photos.occupancy_id = o.id
GROUP BY rooms.id
我知道我可以用 ORM 查询形式写成:
q = (session
.query(
Room,
func.count(func.distinct(Occupancy.resident_id)).label('resident_count'),
func.count(Review.id).label('review_count'),
func.count(Photo.id).label('photo_count'),
(
(3 + func.avg(Review.rating)) / (1 + func.count(Review.rating))
).label('bayesian_rating')
)
.select_from(
join(Room, RoomListing).join(Occupancy).outerjoin(Review).outerjoin(Photo)
)
.group_by(Room.id)
)
for room, res_ct, rev_ct, p_ct in q:
wish_that_I_could_write(room.res_ct, room.rev_ct, room.p_ct, room.score)
但是如何在我的Room 类中将resident_count、review_count 等声明为column_propertys,这样我就不需要每次都构造这个查询了?
【问题讨论】:
标签: python sql orm sqlalchemy