【发布时间】:2015-06-23 16:21:32
【问题描述】:
我遇到了这个异常:
unexpected AST node: query
我的查询是:
SELECT u.user_id, u.username,u.email,u.phone,u.status,r.rolename
FROM user_registration u, roles r
WHERE u.user_id=r.role_id IN (
select ur.role_id from roles ur where ur.role_id=u.user_id
)
此查询在 MySQL 中运行,但在我的应用程序中不起作用
例外是:
SEVERE: Servlet.service() for servlet [spring] in context with path [/jaga] threw exception [Request processing failed; nested exception is org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: in near line 1, column 196 [SELECT u.user_id, u.username,u.email,u.phone,u.status,r.rolename FROM com.jagahunt.admin.usermanagement.entity.User u, com.jagahunt.admin.usermanagement.entity.Role r WHERE u.user_id=r.role_id IN (select ur.role_id from com.jagahunt.admin.usermanagement.entity.Role ur where ur.role_id=u.user_id)]] with root cause
org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node: in near line 1, column 196 [SELECT u.user_id, u.username,u.email,u.phone,u.status,r.rolename FROM com.jagahunt.admin.usermanagement.entity.User u, com.jagahunt.admin.usermanagement.entity.Role r WHERE u.user_id=r.role_id IN (select ur.role_id from com.jagahunt.admin.usermanagement.entity.Role ur where ur.role_id=u.user_id)]
【问题讨论】:
-
WHERE u.user_id=r.role_id IN(select ...。那是无效的。用户 ID 等于某个值,或者它在子选择中。但是你不能像这样连接这两个限制。
标签: java sql hibernate orm abstract-syntax-tree