【发布时间】:2014-11-14 11:42:39
【问题描述】:
我必须在我的表中找到丢失的小时,因为频率 = 1 我必须每小时找到一条记录,如果不是这样,我必须显示丢失的小时。 这是我的代码
declare @StartDate datetime declare @EndDate datetime declare @now datetime set @now = getdate() set @StartDate = dateadd(day,-30,@now) set @EndDate = dateadd(day,-2,@now) Select Flow.Id,Flow.ComponentId, Frequency.Name frequencyName, Flow.MeasurementDate as MeasurementDate, LAG(MeasurementDate) OVER (ORDER BY MeasurementDate) LagValue, abs( DATEDIFF (hour, MeasurementDate, LAG(MeasurementDate) OVER (ORDER BY MeasurementDate) ) ) DifferenceDate , (CASE WHEN DATEDIFF (hour, MeasurementDate, LAG(MeasurementDate) OVER (ORDER BY MeasurementDate) ) > '1' THEN 'Yes' ELSE 'No' END) AS Gap into #tab1 FROM Data.dbo.Flow inner join Data.dbo.Component on flow.ComponentId = Component.Id inner join Data.dbo.Frequency on Flow.Frequency = Frequency.Id Where flow.LoaderCode='TOT' and Flow.Frequency='1' and ScheduledVolume IS NOT NULL and MeasurementDate between @StartDate and @EndDate --and DATEDIFF (hour, MeasurementDate, LAG(MeasurementDate) OVER (ORDER BY MeasurementDate) ) >1 Group By Frequency.Name, Flow.MeasurementDate, Flow.ComponentId select * from #tab1
【问题讨论】:
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这真的是你展示代码的方式吗?
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我无法更好地展示我的代码,它会生成一条错误消息来格式化我的代码...@SubqueryCrunch