如何在 SQL 子查询中使用 NOT IN？ [复制]

Question

我正在尝试查找饮酒者和饮酒者喜欢的饮品，但饮酒者到目前为止还没有订购该饮品。我还需要按饮酒者和饮料的升序对饮酒者和饮料对进行排序。

注意：我只能使用 IN 或 NOT IN 操作。 （我也在 MYSQL 工作）

我对 SQL 非常陌生，因此非常感谢任何建议。

这是我试图从中检索数据的两个表：

CREATE TABLE LIKES( /* Drinkers like drinks */
DRINKER     VARCHAR(30) NOT NULL,   /* Drinker name */
DRINK       VARCHAR(30) NOT NULL,   /* Drink name   */
RATING      DECIMAL(1)  NOT NULL,   /* Rating of the drink  */
    CONSTRAINT LIKES_PKEY PRIMARY KEY(DRINKER, DRINK),
    CONSTRAINT LIKES_FKEY1 FOREIGN KEY(DRINK) REFERENCES ALLDRINKS(DRINK),
    CONSTRAINT LIKES_DKEY2 FOREIGN KEY(DRINKER) REFERENCES DRINKERS(DRINKER));

CREATE TABLE ORDERS(    /* Drinkers visit pubs and consumes drinks */
DRINKER     VARCHAR(30) NOT NULL,   /* Drinker name */
PUB         VARCHAR(30) NOT NULL,   /* Pub name */
ODATE       DATE        NOT NULL,   /* Order date   */
DRINK       VARCHAR(30) NOT NULL,   /* Drink name   */
DRINK_NO    DECIMAL(2)  NOT NULL,   /* A sequence number of a drink */
    CONSTRAINT ORDERS_PKEY PRIMARY KEY(DRINKER, PUB, ODATE, DRINK, DRINK_NO),
    CONSTRAINT ORDERS_FKEY1 FOREIGN KEY(PUB, DRINK) REFERENCES SERVES(PUB, DRINK),
    CONSTRAINT ORDERS_FKEY2 FOREIGN KEY(DRINKER) REFERENCES DRINKERS(DRINKER)   );

这是我的 SELECT 语句：

SELECT DRINKER, DRINK
FROM LIKES
WHERE DRINKER NOT IN 
    (SELECT DRINKER
     FROM ORDERS 
     WHERE ODATE IS NULL)
     AND DRINK NOT IN
         (SELECT DRINK 
          FROM ORDERS 
          WHERE ODATE IS NULL)
          ORDER BY DRINKER AND DRINK ASC; 

Answer 1

除了常见的条件ODATE IS NULL之外，您还可以在子查询中简单地使用NOT EXISTS结合两列：

SELECT l.DRINKER, l.DRINK
  FROM LIKES l
 WHERE NOT EXISTS 
      ( SELECT 0
          FROM ORDERS 
         WHERE ODATE IS NULL
           AND ( DRINKER = l.DRINKER
              OR DRINK = l.DRINK ) )
 ORDER BY l.DRINKER , l.DRINK;

Demo

Answer 2

SELECT l.DRINKER, l.DRINK
FROM LIKES l
WHERE CONCAT(l.DRINKER+'~~'+l.DRINK) NOT IN 
( 
   SELECT CONCAT(O.DRINKER+'~~'+O.DRINK)
   FROM ORDERS O
)
ORDER BY l.DRINKER , l.DRINK ASC;