【发布时间】:2019-11-16 04:38:38
【问题描述】:
我使用 TVP 创建了以下函数。我最初将数据插入 TVP,然后从中进行选择。
CREATE FUNCTION [dbo].employees_data(
@employeeIds NVARCHAR(MAX)
)
RETURNS NVARCHAR(MAX)
-- WITH SCHEMABINDING
AS
BEGIN
CREATE TYPE employees_data
AS TABLE (can_view_all BIT,role_id INT ,employee_id INT);
DECLARE @EmployeeDataTVP AS employees_data;
INSERT INTO @EmployeeDataTVP (can_view_all, role_id, employee_id)
SELECT
ur.role_id,
ua.employee_id
INNER JOIN user_roles ur ON ur.user_account_id = ua.id
WHERE ua.employee_id IN (SELECT * FROM STRING_SPLIT(@employeeIds, ','));
RETURN (SELECT
(
CASE
WHEN ed.role_id = 1 THEN (
SELECT
cc.id,
ISNULL(cc.standard_name, cc.localized_name) AS name,
cc.client_cost_center_id AS cost_center_id
FROM s eccs
LEFT JOIN centers cc on eccs.center_id = cc.id
WHERE eccs.employee_id = ed.employee_id
FOR JSON PATH
)
ELSE NULL
END
) AS managed_places,
ed.employee_id
FROM @EmployeeDataTVP ed
)
END
但是当我执行该函数时,我得到了Must declare the table variable \"@EmployeeDataTVP\". 错误。我无法弄清楚我做错了什么。
【问题讨论】:
-
table-valued parameter 在哪里?您应该使用一个而不是逗号分隔的值列表。
标签: sql-server tsql table-variable