检查行是否存在 PDO [重复]

Question

我想不通，我一直在阅读大量堆栈溢出线程，但我一直遇到问题，

现在，如果用户输入任何内容，无论是相同的用户名还是电子邮件，都会出现错误。请帮忙！

我希望在用户键入数据库中已有的用户名或电子邮件时显示错误消息。

$sql = "SELECT count(*) FROM users WHERE user_email = :email OR user_name = :username";
        $query1 = $DBH->prepare($sql);
        $query1->execute(array(':username'  => $username,':email' => $email));

        if ($query1->rowCount() > 0){
            // User Exists
            $error = "Username or E-Mail in Use";

        }   else{
            // User Does Not Exist
            //No errors - let’s create the account
            //Encrypt the password with a salt
            $encryptedPass = password_hash($_POST['password'], PASSWORD_DEFAULT);
            //Insert DB
            $query = "INSERT INTO users (user_email, user_password, user_forename, user_lastname, user_name, user_gender, user_country, user_number) VALUES (:email, :password, :firstname, :lastname, :username, :gender, :country, :mobile)";
            $result = $DBH->prepare($query);
            $result->bindParam(':username', $_POST['username']);
            $result->bindParam(':firstname', $_POST['firstname']);
            $result->bindParam(':lastname', $_POST['lastname']);
            $result->bindParam(':email', $_POST['email']);
            $result->bindParam(':gender', $_POST['gender']);
            $result->bindParam(':country', $_POST['country']);
            $result->bindParam(':mobile', $_POST['mobile']);
            $result->bindParam(':password', $encryptedPass);

            if($result->execute()){
                echo '<div class="alert alert-success" role="alert">Registration Successful!</div>';
                echo "<script> window.location.assign('index.php?p=login'); </script>";
            }
        }

编辑

        $stmt = $DBH->prepare("SELECT COUNT(*) FROM users WHERE user_email = :email OR user_name = :username");
        $stmt->execute(array(':username'  => $username,':email' => $email));
        $count = $stmt->fetchColumn();

        var_dump($count);

        if ($count > 0) {
            $error1 = "Username or E-Mail in Use. Please try another.";
        }

        if(!$error){

                //No errors - let’s create the account
                //Encrypt the password with a salt
                $encryptedPass = password_hash($_POST['password'], PASSWORD_DEFAULT);
                //Insert DB
                $query = "INSERT INTO users (user_email, user_password, user_forename, user_lastname, user_name, user_gender, user_country, user_number) VALUES (:email, :password, :firstname, :lastname, :username, :gender, :country, :mobile)";
                $result = $DBH->prepare($query);
                $result->bindParam(':username', $_POST['username']);
                $result->bindParam(':firstname', $_POST['firstname']);
                $result->bindParam(':lastname', $_POST['lastname']);
                $result->bindParam(':email', $_POST['email']);
                $result->bindParam(':gender', $_POST['gender']);
                $result->bindParam(':country', $_POST['country']);
                $result->bindParam(':mobile', $_POST['mobile']);
                $result->bindParam(':password', $encryptedPass);

                if($result->execute()){
                    echo '<div class="alert alert-success" role="alert">Registration Successful!</div>';
                    // echo "<script> window.location.assign('index.php?p=login'); </script>";
                }
            }

var dump = string(1) "0"

Answer 1

解决此问题的几种方法。正如@chris85 提到的，您需要实际获取结果而不是使用rowCount()。

编辑：删除了第一个示例。

<?php
$stmt = $pdo->prepare("SELECT COUNT(*) FROM users WHERE user_email = :email OR user_name = :username");
$stmt->execute(array(':username'  => $username,':email' => $email));
$count = $stmt->fetchColumn();

if ($count > 0) {
    $error = "Username or E-Mail in Use";
} else {
    ...