如何在sql中检查表中是否存在所有元素？

Question

我在 PHP 中有任何主题 ID 数组，比如说

['abc123', 'bcd3432', 'bla232', ....]

这是我在 sql oracle 中的错误尝试

select
  *
from
  subject_table
where
  subject_id IN ('abc123', 'bcd3432', 'bla232'....)

如果有主题，则返回true，否则返回false

我如何实现它？

Answer 1

你需要一个不同的计数来知道是否所有的 subject_ids 都在哪里。

select case when count(distinct subject_id) = 3 then 'true' else 'false' end as status 
  from subject_table
 where subject_id in('abc123', 'bcd3432', 'bla232')

Answer 2

尝试：

select
  case when count(1) > 0 then 'true' else 'false' end
from
  subject_table
where
  subject_id IN ('abc123', 'bcd3432', 'bla232')

Answer 3

如果你设置 > 0 为真，0 为假，你可以这样选择：

select count(*)  as Existed
from
  subject_table
where
  subject_id IN ('abc123', 'bcd3432', 'bla232'....)

Answer 4

将数组作为集合传递：

CREATE OR REPLACE TYPE StringList IS TABLE OF VARCHAR2(20);
/

那么你可以这样做：

SELECT CASE
       WHEN EXISTS (
              SELECT 1
              FROM   subject_table
              WHERE  StringList( 'abc123', 'bcd3432', 'bla232' )
                     SUBMULTISET OF
                     CAST( COLLECT( subject_id ) AS StringList )
            )
       THEN 'true'
       ELSE 'false'
       END AS has_all_ids
FROM   DUAL;

您甚至可以使用bind parameter to pass the array in：

SELECT CASE
       WHEN EXISTS (
              SELECT 1
              FROM   subject_table
              WHERE  :your_array
                     SUBMULTISET OF
                     CAST( COLLECT( subject_id ) AS StringList )
            )
       THEN 'true'
       ELSE 'false'
       END AS has_all_ids
FROM   DUAL;

Answer 5

你可以试试这个。这里我将包含所有元素的字符串拆分为一组行，并将其与主表与LEFT JOIN进行比较

WITH     given_sub
     AS (    SELECT DISTINCT TRIM (REGEXP_SUBSTR ('abc123,bcd3432,bla232',
                                                  '[^,]+',
                                                  1,
                                                  LEVEL))
                                subject_id
               FROM DUAL
         CONNECT BY INSTR ('abc123,bcd3432,bla232',
                           ',',
                           1,
                           LEVEL - 1) > 0)
SELECT CASE
          WHEN COUNT (DISTINCT s.subject_id) < COUNT (DISTINCT g.subject_id)
          THEN
             'FALSE'
          ELSE
             'TRUE'
       END
          All_found
  FROM given_sub g
       LEFT OUTER JOIN subject_table s
          ON     s.subject_id = g.subject_id
             AND s.subject_id IN ('abc123',
                                  'bcd3432',
                                  'bla232'
                                  );