聚合来自 2 个表 oracle SQL 的数据答案

【问题标题】：aggregate data from 2 tables oracle SQL聚合来自 2 个表 oracle SQL 的数据
【发布时间】：2021-10-01 09:29:58
【问题描述】：

我在 3 个表中有这些数据：

表 1：BU

BU_CODE	ARCHIVE_FLG
1001	Y
1002	Y
1003	Y
1004	N
1005	Y

表 2：STG_ACCOUNT

BU_CODE	ACCOUNT_ID
1001	A0001
1001	A0003
1002	A0002

表 3：STG_CONTRACT

BU_CODE	CONTRACT_ID
1002	C0001
1002	C0002

这两个查询工作正常：

查询 1：

SELECT
T2.BU_CODE, COUNT(T1.ACCOUNT_ID) AS COUNT_OF_ACCOUNT
FROM STG_ACCOUNT T1
FULL JOIN S_BU T2 ON T2.BU_CODE = T1.BU_CODE
WHERE T2.ARCHIVE_FLG = '1'
GROUP BY T2.BU_CODE
ORDER BY T2.BU_CODE;

BU_CODE	COUNT_OF_ACCOUNT
1001	2
1002	1
1003	0
1005	0

查询 2：

SELECT
T2.BU_CODE, COUNT(T1.CONTRACT_ID) AS COUNT_OF_CONTRACT
FROM STG_CONTRACT T1
FULL JOIN S_BU T2 ON T2.BU_CODE = T1.BU_CODE
WHERE T2.ARCHIVE_FLG = '1'
GROUP BY T2.BU_CODE
ORDER BY T2.BU_CODE;

BU_CODE	COUNT_OF_CONTRACT
1001	0
1002	2
1003	0
1005	0

现在我想合并这两个查询的结果以显示更优雅的输出：

BU_CODE	COUNT_OF_ACCOUNT	COUNT_OF_CONTRACT
1001	2	0
1002	1	2
1003	0	0
1005	0	0

什么 Oracle SQL 函数可以帮助我？

【问题讨论】：

感谢您的格式化问题，请查看此链接asktom.oracle.com/pls/apex/…

标签： oracle

【解决方案1】：

一个选项可能是使用CTE 表达式

with x as 
( 
SELECT
T2.BU_CODE, COUNT(T1.ACCOUNT_ID) AS COUNT_OF_ACCOUNT
FROM STG_ACCOUNT T1
FULL JOIN S_BU T2 ON T2.BU_CODE = T1.BU_CODE
WHERE T2.ARCHIVE_FLG = '1'
GROUP BY T2.BU_CODE
ORDER BY T2.BU_CODE
), 
y as 
( 
SELECT
T2.BU_CODE, COUNT(T1.CONTRACT_ID) AS COUNT_OF_CONTRACT
FROM STG_CONTRACT T1
FULL JOIN S_BU T2 ON T2.BU_CODE = T1.BU_CODE
WHERE T2.ARCHIVE_FLG = '1'
GROUP BY T2.BU_CODE
ORDER BY T2.BU_CODE
) 
select x.bu_code , x.count_of_account, y.count_of_contract 
from x join y on x.bu_code=y.bu_code

【讨论】：

【解决方案2】：

您可以加入两个表。

SELECT
T1.BU_CODE AS BU_CODE, COUNT(DISTINCT T2.ACCOUNT_ID) AS COUNT_OF_ACCOUNT, COUNT(DISTINCT T3.CONTRACT_ID) AS COUNT_OF_CONTRACT
FROM S_BU T1
LEFT JOIN STG_ACCOUNT T2 ON T1.BU_CODE = T2.BU_CODE
LEFT JOIN STG_CONTRACT T3 ON T1.BU_CODE = T3.BU_CODE
WHERE T1.ARCHIVE_FLG = '1'
GROUP BY T1.BU_CODE
ORDER BY T1.BU_CODE;

【讨论】：