Select into Table from Table2 where column in (Subquery)答案

【问题标题】：Select into Table from Table2 where column in (Subquery)Select into Table from Table2 where column in (Subquery)
【发布时间】：2014-04-02 13:44:27
【问题描述】：

SELECT .... ColumnNames ...
INTO [FOUND_DUPLICATES] 
FROM [FIND_DUPLICATES] AS FD
WHERE FD.[Contract No] IN 
    (SELECT [Contract No],
            [Vehicle Identity number (VIN)],
            COUNT(*) AS Anzahl 
    FROM FIND_DUPLICATES
    GROUP BY 
            [Contract No],
            [Vehicle Identity number (VIN)]
    HAVING COUNT(*) >1)

在这里你可以看到我想要的:)

查找重复项并将它们复制到另一个表中。但是使用这段代码我得到一个错误：

选择列表中只能指定一个表达式，当 EXISTS 没有引入子查询。

用于查找重复项的 SELECT 语句运行良好。但是我无法使用 Select Into 仅选择重复项并将其复制到新表中。

我希望你能理解我想要什么，任何人都可以帮助我:)

//编辑：我正在使用 SQL Server 2008 R2

【问题讨论】：

嗯...我的缩进有点错误，但这应该有助于提高可读性。

标签： sql sql-server select select-into

【解决方案1】：

添加另一个子查询应该可以吗？

Select  .... ColumnNames ...

INTO [FOUND_DUPLICATES] 
    FROM [FIND_DUPLICATES]
    AS FD
    where FD.[Contract No] 
       IN (  Select [Contract No] from (Select 
        [Contract No],
        [Vehicle Identity number (VIN)],
        COUNT(*) AS Anzahl 
    from FIND_DUPLICATES
    group by 
        [Contract No],
        [Vehicle Identity number (VIN)]
    having count(*) >1)x)

【讨论】：

【解决方案2】：

你可以用这个：

SELECT  .... ColumnNames ...

INTO [FOUND_DUPLICATES] 
FROM [FIND_DUPLICATES] AS FD
WHERE FD.[Contract No] IN
(
  SELECT 
    [Contract No]
  FROM FIND_DUPLICATES
  GROUP BY 
     [Contract No],
     [Vehicle Identity number (VIN)]
  HAVING COUNT(*) >1
)

或使用相关子查询：

SELECT .... ColumnNames ...

INTO [FOUND_DUPLICATES] 
FROM [FIND_DUPLICATES] AS FD
WHERE EXISTS 
(
    SELECT 1
    FROM FIND_DUPLICATES FD1
    WHERE FD.[Contract No] = FD1.[Contract No]
    GROUP BY 
        FD1.[Contract No],
        FD1.[Vehicle Identity number (VIN)]
    HAVING COUNT(*) >1
)

【讨论】：

【解决方案3】：

Select  .... ColumnNames ...

INTO [FOUND_DUPLICATES] 
    FROM [FIND_DUPLICATES]
    AS FD
    where FD.[Contract No] 
       IN (
       select [Contract No] from (Select --inner sub query 
        [Contract No],
        [Vehicle Identity number (VIN)],
        COUNT(*) AS Anzahl 
    from FIND_DUPLICATES
    group by 
        [Contract No],
        [Vehicle Identity number (VIN)]
    having count(*) >1) )

【讨论】：