【发布时间】:2021-12-02 18:21:09
【问题描述】:
我有以下表格:
CREATE TABLE Categorie
(categ_id NUMBER(5,0),
tip VARCHAR2(20));
CREATE TABLE Reteta
(reteta_id NUMBER(3),
nume VARCHAR2(100),
descriere VARCHAR2(200),
categ_id NUMBER(3,0),
vegetariana VARCHAR2(1) CHECK (vegetariana IN ('D','N')),
timp_preparare NUMBER(20,1),
portii NUMBER(3,1));
CREATE TABLE Set_ingrediente
(reteta_id NUMBER(3,0),
ingred_id NUMBER(3,0),
cantitate NUMBER(5,2),
um VARCHAR2(10) NOT NULL CHECK (um IN ('gr','ml','buc','lingurita','cana')),
comentarii VARCHAR2(100)
);
CREATE TABLE Ingredient
(ingred_id NUMBER(3,0),
ingredient VARCHAR2(30));
以及以下主键/外键:
ALTER TABLE Categorie
MODIFY (categ_id CONSTRAINT categ_id_pk PRIMARY KEY NOT NULL);
ALTER TABLE Reteta
MODIFY(CONSTRAINT reteta_id_pk PRIMARY KEY (reteta_id));
ALTER TABLE Ingredient
MODIFY(CONSTRAINT ingred_id_pk PRIMARY KEY (ingred_id));
ALTER TABLE Set_ingrediente
MODIFY( CONSTRAINT reteta_id_fk FOREIGN KEY (reteta_id) REFERENCES Reteta(reteta_id) ON DELETE CASCADE);
ALTER TABLE Set_ingrediente
MODIFY( CONSTRAINT ingred_id_fk FOREIGN KEY (ingred_id) REFERENCES Ingredient(ingred_id) ON DELETE CASCADE);
我必须编写一个触发器: 如果食谱使用“油”成分,请确保素食栏不能更改。 这是我尝试过的触发器,但它不起作用:
CREATE OR REPLACE TRIGGER tr_oil BEFORE UPDATE
ON Reteta
FOR EACH ROW BEGIN
DECLARE
ingredient_var ingredient.ingredient%type;
SELECT ingredient
INTO ingredient_var
FROM Ingredint
WHERE ingred_id=
(SELECT ingred_id
FROM Set_ingrediente
WHERE reteta_id=NEW.reteta_id);
IF ingredient_var='oil' THEN
SET NEW.vegetariana = OLD.vegetariana;
END IF;
END;
【问题讨论】: