【问题标题】:TSQL - Filter group if it contains all nullTSQL - 过滤组,如果它包含所有空
【发布时间】:2018-11-15 10:44:47
【问题描述】:

我想过滤掉包含 TASK_START 和 TASK_END 的所有空值的组,即 B 和 D。

示例表数据

+----+-------+-------------------------+-------------------------+-------------------------+-------------------------+
| ID | STATE |       ENTER_STATE       |       LEAVE_STATE       |       TASK_START        |        TASK_END         |
+----+-------+-------------------------+-------------------------+-------------------------+-------------------------+
| A  | UP    | 2018-11-11 08:00:00.000 | 2018-11-11 08:30:00.000 | 2018-11-11 08:00:00.000 | 2018-11-11 08:10:00.000 |
| A  | UP    | 2018-11-11 09:00:00.000 | 2018-11-11 09:30:00.000 | NULL                    | NULL                    |
| A  | UP    | 2018-11-11 10:00:00.000 | 2018-11-11 10:30:00.000 | 2018-11-11 08:20:00.000 | 2018-11-11 08:30:00.000 |
| B  | UP    | 2018-11-11 08:00:00.000 | 2018-11-11 09:00:00.000 | NULL                    | NULL                    |
| B  | UP    | 2018-11-11 09:00:00.000 | 2018-11-11 10:00:00.000 | NULL                    | NULL                    |
| B  | UP    | 2018-11-11 10:20:00.000 | 2018-11-11 11:00:00.000 | NULL                    | NULL                    |
| B  | UP    | 2018-11-11 11:00:00.000 | 2018-11-11 12:00:00.000 | NULL                    | NULL                    |
| C  | UP    | 2018-11-11 08:00:00.000 | 2018-11-11 08:20:00.000 | 2018-11-11 08:15:00.000 | 2018-11-11 08:30:00.000 |
| C  | UP    | 2018-11-11 08:20:00.000 | 2018-11-11 08:30:00.000 | 2018-11-11 08:20:00.000 | 2018-11-11 08:35:00.000 |
| D  | UP    | 2018-11-11 08:00:00.000 | 2018-11-11 08:10:00.000 | NULL                    | NULL                    |
| D  | UP    | 2018-11-11 08:10:00.000 | 2018-11-11 09:10:00.000 | NULL                    | NULL                    |
+----+-------+-------------------------+-------------------------+-------------------------+-------------------------+

【问题讨论】:

    标签: sql sql-server tsql sql-server-2012


    【解决方案1】:

    试试这个:

    DECLARE @DataSource TABLE
    (
        [ID] CHAR(1)
       ,[STATE] CHAR(2)
       ,[ENTER_STATE] DATETIME2(0)
       ,[LEAVE_STATE] DATETIME2(0)
       ,[TASK_START] DATETIME2(0)
       ,[TASK_END] DATETIME2(0)
    );
    
    INSERT INTO @DataSource
    VALUES ('A', 'UP', '2018-11-11 08:00:00.000', '2018-11-11 08:30:00.000', '2018-11-11 08:00:00.000', '2018-11-11 08:10:00.000')
          ,('A', 'UP', '2018-11-11 09:00:00.000', '2018-11-11 09:30:00.000', NULL, NULL)
          ,('A', 'UP', '2018-11-11 10:00:00.000', '2018-11-11 10:30:00.000', '2018-11-11 08:20:00.000', '2018-11-11 08:30:00.000')
          ,('B', 'UP', '2018-11-11 08:00:00.000', '2018-11-11 09:00:00.000', NULL, NULL)
          ,('B', 'UP', '2018-11-11 09:00:00.000', '2018-11-11 10:00:00.000', NULL, NULL)
          ,('B', 'UP', '2018-11-11 10:20:00.000', '2018-11-11 11:00:00.000', NULL, NULL)
          ,('B', 'UP', '2018-11-11 11:00:00.000', '2018-11-11 12:00:00.000', NULL, NULL)
          ,('C', 'UP', '2018-11-11 08:00:00.000', '2018-11-11 08:20:00.000', '2018-11-11 08:15:00.000', '2018-11-11 08:30:00.000')
          ,('C', 'UP', '2018-11-11 08:20:00.000', '2018-11-11 08:30:00.000', '2018-11-11 08:20:00.000', '2018-11-11 08:35:00.000')
          ,('D', 'UP', '2018-11-11 08:00:00.000', '2018-11-11 08:10:00.000', NULL, NULL)
          ,('D', 'UP', '2018-11-11 08:10:00.000', '2018-11-11 09:10:00.000', NULL, NULL);
    
    WITH DataSource AS
    (
        SELECT *
             ,MAX([TASK_START]) OVER (PARTITION BY [ID]) AS [DateStart]
             ,MAX([TASK_END]) OVER (PARTITION BY [ID]) AS [DateEnd]
        FROM @DataSource
    )
    SELECT *
    FROM DataSource
    WHERE NOT ([DateStart] IS NULL AND [DateEnd] IS NULL);   
    

    我们的想法是获取每个组的最大(或最小)日期,然后,如果存在此值为 NULL 的行,则排除它们。

    【讨论】:

      【解决方案2】:

      你可以使用not exists

      select t.*
      from table t
      where not exists (select 1 
                        from table t1 
                        where t1.id = t.id and t1.task_start is not null and t1.task_end is not null
                       );
      

      其他选项将使用GROUP BY

      select id
      from table t
      group by id
      having sum(case when task_start is not null then 1 else 0  end) = 0 and
             sum(case when task_end is not null then 1 else 0  end) = 0;
      

      【讨论】:

      • 不会也从 A 中删除该字段吗?
      • @Kyrive。 . .是的,它会删除A,因为TASK_START & TASK_END 不为空。
      【解决方案3】:

      我会简单地将count()having 一起使用:

      select id
      from table t
      group by id
      having count(task_start) = 0 and
             count(task_end) = 0;
      

      【讨论】:

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