Spark - PySpark sql 错误

Question

我有一个简单的 pyspark 代码，但我无法运行它。我尝试在 Ubuntu 系统上运行它并使用 PyCharm IDE。我想连接到 Oracle XE 数据库并且我想打印我的测试表。

我的 spark python 代码来了：

from pyspark import SparkContext
from pyspark.sql import SQLContext

sc = SparkContext()

sqlContext = SQLContext(sc)

demoDf = sqlContext.read.format("jdbc").options(
    url="jdbc:oracle:thin:@10.10.10.10:1521:XE",
    driver="oracle.jdbc.driver.OracleDriver",
    table="tst_table",
    user="xxx",
    password="xxx").load()

demoDf.show()

这是我的踪迹：

Traceback (most recent call last):
  File "/home/kebodev/PycharmProjects/spark_tst/cucc_spark.py", line 13, in <module>
    password="xxx").load()
  File "/home/kebodev/spark-2.0.1/python/pyspark/sql/readwriter.py", line 153, in load
    return self._df(self._jreader.load())
  File "/home/kebodev/spark-2.0.1/python/lib/py4j-0.10.3-src.zip/py4j/java_gateway.py", line 1133, in __call__
  File "/home/kebodev/spark-2.0.1/python/pyspark/sql/utils.py", line 63, in deco
    return f(*a, **kw)
  File "/home/kebodev/spark-2.0.1/python/lib/py4j-0.10.3-src.zip/py4j/protocol.py", line 319, in get_return_value
py4j.protocol.Py4JJavaError: An error occurred while calling o27.load.
: java.lang.RuntimeException: Option 'dbtable' not specified
    at scala.sys.package$.error(package.scala:27)
    at org.apache.spark.sql.execution.datasources.jdbc.JDBCOptions$$anonfun$2.apply(JDBCOptions.scala:30)
    at org.apache.spark.sql.execution.datasources.jdbc.JDBCOptions$$anonfun$2.apply(JDBCOptions.scala:30)
    at scala.collection.MapLike$class.getOrElse(MapLike.scala:128)
    at org.apache.spark.sql.execution.datasources.CaseInsensitiveMap.getOrElse(ddl.scala:117)
    at org.apache.spark.sql.execution.datasources.jdbc.JDBCOptions.<init>(JDBCOptions.scala:30)
    at org.apache.spark.sql.execution.datasources.jdbc.JdbcRelationProvider.createRelation(JdbcRelationProvider.scala:33)
    at org.apache.spark.sql.execution.datasources.DataSource.resolveRelation(DataSource.scala:330)
    at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:149)
    at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:122)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:498)
    at py4j.reflection.MethodInvoker.invoke(MethodInvoker.java:237)
    at py4j.reflection.ReflectionEngine.invoke(ReflectionEngine.java:357)
    at py4j.Gateway.invoke(Gateway.java:280)
    at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:132)
    at py4j.commands.CallCommand.execute(CallCommand.java:79)
    at py4j.GatewayConnection.run(GatewayConnection.java:214)
    at java.lang.Thread.run(Thread.java:745)


Process finished with exit code 1

有人可以帮助我吗？

Answer 1

像这样从table改成dbtable，

demoDf = sqlContext.read.format("jdbc").options(
    url="jdbc:oracle:thin:@10.10.10.10:1521:XE",
    driver="oracle.jdbc.driver.OracleDriver",
    dbtable="tst_table",
    user="xxx",
    password="xxx").load()

Answer 2

试试这样的：

def testQuery(query):
        df = sqlContext.read.format("jdbc").options(
             url="jdbc:oracle:thin:@10.10.10.10:1521:XE",
             driver="oracle.jdbc.driver.OracleDriver",
             dbtable="( " + query + " ) as temp",
             user="xxx",
             password="xxx").load()
        return df