【发布时间】:2018-07-19 05:06:58
【问题描述】:
PFB 我用过的代码:
ResultSet rs1 = stmt.executeQuery("select dfd.document_id,dfd.country_id,dfi.folder_name from dossier_folder_documents dfd,dossier_folder_info dfi where dfd.fk_dossier_folder_id=dfi.pk_dossier_folder_id and dfd.is_core is null and dfd.action='N' and dfd.fk_dossier_basic_info_id in (select pk_dossier_id from dossier_basic_info where dossier_id= '"+vdlist.get(g)+"' and (dfd.document_id,dfi.folder_name) not in(select dfd.document_id,dfi.folder_name from dossier_folder_documents dfd,dossier_folder_info dfi where dfd.fk_dossier_folder_id=dfi.pk_dossier_folder_id and dfd.fk_dossier_basic_info_id in (select pk_dossier_id from dossier_basic_info where dossier_id= '"+sdlist.get(g)+"' and data_state='C')))");
ResultSet rs2 = stmt.executeQuery("select dfd.document_id,dfd.country_id,dfi.folder_name from dossier_folder_documents dfd,dossier_folder_info dfi where dfd.fk_dossier_folder_id=dfi.pk_dossier_folder_id and dfd.is_core is null and dfd.action='O' and dfd.fk_dossier_basic_info_id in (select pk_dossier_id from dossier_basic_info where dossier_id='"+vdlist.get(g)+"') and (dfd.document_id,dfi.folder_name) in (select dfd.document_id,dfi.folder_name from dossier_folder_documents dfd,dossier_folder_info dfi where dfd.fk_dossier_folder_id=dfi.pk_dossier_folder_id and dfd.fk_dossier_basic_info_id in (select pk_dossier_id from dossier_basic_info where dossier_id='"+sdlist.get(g)+"' and data_state='C'))");
ResultSetMetaData rsmd1 = rs1.getMetaData();
//ResultSetMetaData rsmd2 = rs2.getMetaData();
String temp5 = new String();
for(int f=1;f<=rsmd1.getColumnCount();f++)
{
data3+=rsmd1.getColumnName(f)+"/ /";}
temp4=data3;
data3="";
while(rs1.next())
{
System.out.println("In here...");
num2=g;
for(int x=1;x<=rsmd1.getColumnCount();x++)
{
temp5+=rs1.getString(x)+"/ /";
}
String data5 = new String();
data5=temp5;
sublist1.add(data5);
//System.out.println(sublist);
errvdlist.add(vdlist.get(num2));
errsdlist.add(sdlist.get(num2));
System.out.println("Validation Dossier ID for New Corruption: "+vdlist.get(num2));
System.out.println("Submission Dossier ID for New Corruption: "+sdlist.get(num2));
}
while(rs2.next() )
{
num2=g;
for(int x=1;x<=rsmd1.getColumnCount();x++)
{
temp6+=rs2.getString(x)+"/ /";
}
//String data6 = new String();
data6=temp6;
sublist2.add(data6);
//System.out.println(sublist);
errvdlist.add(vdlist.get(num2));
errsdlist.add(sdlist.get(num2));
System.out.println("Validation Dossier ID for Old: "+vdlist.get(num2));
System.out.println("Submission Dossier ID for Old: "+sdlist.get(num2));
}
}
我必须执行两个查询,并且我使用了两个结果集:rs1 和 rs2。在我的输出中,执行了 rs2 的 while 循环,但没有执行 rs1。我最初认为我用于 rs1 的查询有问题,但事实并非如此。打印 'In here...' 的打印语句不会被执行,这意味着它甚至不会进入循环。有什么建议吗?
【问题讨论】:
-
你确定如果你在数据库中运行 rs1 的查询然后获取数据?
-
是的,我试过直接在数据库中运行它。它返回一行。
-
为什么在处理第一条语句的结果之前执行第二条语句?
-
请看这个,也许对你有帮助stackoverflow.com/questions/8579613/…