【发布时间】:2018-09-06 03:02:55
【问题描述】:
我正在尝试实现 olap4j-xmlaserver 以通过 HTTP/XMLA 访问 Mondrian。我编译了项目,创建了一个 war 文件(包括一个 web.xml 文件)并将其部署在 Tomcat 7 中。问题是当数据透视客户端应用程序发送 XMLA 请求时出现异常:
Caused by: org.apache.commons.dbcp.SQLNestedException: Cannot create JDBC driver of class 'com.mysql.jdbc.Driver' for connect URL 'jdbc:mondrian:Jdbc=jdbc:mysql://localhost:3306/foodmart?user=root&password=xxx;Catalog=/WEB-INF/FoodMart.xml'
at org.apache.commons.dbcp.BasicDataSource.createConnectionFactory(BasicDataSource.java:1452)
at org.apache.commons.dbcp.BasicDataSource.createDataSource(BasicDataSource.java:1371)
at org.apache.commons.dbcp.BasicDataSource.getConnection(BasicDataSource.java:1044)
at mondrian.xmla.impl.Olap4jXmlaServlet$Olap4jPoolingConnectionFactory.getConnection(Olap4jXmlaServlet.java:300)
at mondrian.xmla.XmlaHandler.getConnection(XmlaHandler.java:2917)
... 33 more
Caused by: java.sql.SQLException: No suitable driver at java.sql.DriverManager.getDriver (DriverManager.java:315)
at org.apache.commons.dbcp.BasicDataSource.createConnectionFactory(BasicDataSource.java:1437)
... 37 more
我放在一起的web.xml(我在olap4j-xmlaserver 项目中找不到样本)。我确定这个web.xml 文件需要修复才能解决问题,尤其是连接字符串:
<web-app ....
<display-name>olap4j-xmlaserver</display-name>
<description>
Olap4J XML/A server
</description>
<servlet>
<servlet-name>xmla</servlet-name>
<servlet-class>mondrian.xmla.impl.Olap4jXmlaServlet</servlet-class>
<init-param>
<param-name>OlapDriverClassName</param-name>
<param-value>com.mysql.jdbc.Driver</param-value>
</init-param>
<init-param>
<param-name>OlapDriverConnectionString</param-name>
<param-value>
jdbc:mondrian:Jdbc=jdbc:mysql://localhost:3306/foodmart?user=root&password=xxx;Catalog=/WEB-INF/FoodMart.xml
</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>xmla</servlet-name>
<url-pattern>/xmla</url-pattern>
</servlet-mapping>
</web-app>
任何关于如何修复 web.xml 配置的想法或指向相关文档的指针将不胜感激。
【问题讨论】: