如何根据 Id 从多个表中获取值并根据 id 创建新表

Question

我需要一些帮助，我在其他帖子中寻找解决方案，但无法使这些解决方案发挥作用。

我有一个包含一堆 id 的表...

table1

customerId | adsId | campaignId |   contextId   |    Date    | amoutDue
------------------------------------------------------------------------
1234341233 | 4r4w3 |  cp123sifs | cbgvss23r23dd | 03-09-2021 |    50
4556666666 | 35533 |  cp453f44f | cb2d3d23dd33d | 04-06-2021 |    25
3444468766 | 12345 |  cpef4f44r | ccascasca333s | 23-04-2021 |    13
6346522452 | qw324 |  cpfe4r333 | c23ddsasssd2f | 12-07-2021 |    71
3463466346 | 23423 |  cp1vt5rfr | kjhcbwiytcubp | 25-02-2021 |    41
4534634346 | 534f3 |  cp4343ff4 | apisuchha9shh | 14-05-2021 |    36
7743646346 | wer32 |  cp4ffwefe | cq98hd98ladse | 12-03-2021 |    53
2424233335 | r4w4r |  cpwerewff | q09jucidnionc | 05-06-2021 |    65

在另一个表中，我有 adsId 和 adsName：

table2(adsId/adsName)

  adsName  | adsId 
--------------------
ad-google1 | 4r4w3 
ad-fbtests | 35533
ad-bingpro | 12345 
ad-maillan | qw324 
ad-cp-e312 | 23423 
ad-gads2-4 | 534f3 
ad-adProsk | wer32 
ad-cpcB151 | r4w4r 

在第三张桌子上我有campaingName 和campaingId：

table3(campaingId/campaignName)

campaignName | campaignId
------------------------
cp-adWords   | cp123sifs 
cp-looki12   | cp453f44f
cp-cvccp53   | cpef4f44r
cp-Pliiltr   | cpfe4r333
cp-Yellinf   | cp1vt5rfr
cp-Iuliucs   | cp4343ff4
cp-Ieventx   | cp4ffwefe
cp-Shoofab   | cpwerewff

最后是第四张桌子我有contextId和contextName：

table4(contextId/contextName)

   contextId   | contextName 
-----------------------------
 cbgvss23r23dd | ctx-Okkels  
 cb2d3d23dd33d | ctx-Yumeis  
 ccascasca333s | ctx-Niehok   
 c23ddsasssd2f | ctx-Sluiru 
 kjhcbwiytcubp | ctx-Strogi 
 apisuchha9shh | ctx-Slucha 
 cq98hd98ladse | ctx-Epuent 
 q09jucidnionc | ctx-Igeegs 

我正在寻找的是第 5 个表，它从其他表（包含 id）中获取所有名称并给出名称：

table5

customerId | adsId | campaignId |   contextId   |    Date    | amoutDue |   adsName  |campaignName| contextName
---------------------------------------------------------------------------------------------------------------------
1234341233 | 4r4w3 |  cp123sifs | cbgvss23r23dd | 03-09-2021 |    50    | ad-google1 | cp-adWords | ctx-Okkels
4556666666 | 35533 |  cp453f44f | cb2d3d23dd33d | 04-06-2021 |    25    | ad-fbtests | cp-looki12 | ctx-Yumeis
3444468766 | 12345 |  cpef4f44r | ccascasca333s | 23-04-2021 |    13    | ad-bingpro | cp-cvccp53 | ctx-Niehok
6346522452 | qw324 |  cpfe4r333 | c23ddsasssd2f | 12-07-2021 |    71    | ad-maillan | cp-Pliiltr | ctx-Sluiru
3463466346 | 23423 |  cp1vt5rfr | kjhcbwiytcubp | 25-02-2021 |    41    | ad-cp-e312 | cp-Yellinf | ctx-Strogi
4534634346 | 534f3 |  cp4343ff4 | apisuchha9shh | 14-05-2021 |    36    | ad-gads2-4 | cp-Iuliucs | ctx-Slucha
7743646346 | wer32 |  cp4ffwefe | cq98hd98ladse | 12-03-2021 |    53    | ad-adProsk | cp-Ieventx | ctx-Epuent
2424233335 | r4w4r |  cpwerewff | q09jucidnionc | 05-06-2021 |    65    | ad-cpcB151 | cp-Shoofab | ctx-Igeegs

我尝试使用join，但无法选择所有表...我的 SQL 语句是：

get campaingName from table 2 and create a row with the name where campaingId from table1 = to campaingId from table 2 所有字段都相同...

提前致谢！

Answer 1

你会像这样使用join

select *
from table1 t1 join
     table2 t2
     using (adsid) join
     table3 t3
     using (campaignid) join
     table4 t4
     using (contextid);

上述方法有效，因为join 键在引用表和原始表中具有相同的名称（最佳实践）。你也可以使用更详细的：

select t1.*, t2.adsName, t3.campaignName, t4.contextName
from table1 t1 join
     table2 t2
     on t2.adsid = t1.adsid join
     table3 t3
     on t3.campaignid = t1.campaignid join
     table4 t4
     on t4.contextid = t1.contextid;

如果缺少某些 id，则使用 left join 而不是 join。

Answer 2

您可以在大查询中使用多个 with 子句来实现这一点。

WITH TEST1 AS
(select a1.*,a2.adsName
from `<project_name.<dataset_name>.table1` a1, `<project_name.<dataset_name>.table2` a2
where a1.adsId=a2.adsId),
TEST2 as
(
select TEST1.*,a3.campaignName
from TEST1, `<project_name.<dataset_name>.table3` a3
WHERE TEST1.campaignId=a3.campaignId)

select TEST2.*, a4.contextName
from TEST2,`<project_name.<dataset_name>.table4` a4
WHERE TEST2.contextId=a4.contextId