【发布时间】:2013-05-29 14:43:07
【问题描述】:
我的视图如下 - 它编译得很好,但是当我尝试从中选择时,我得到 ORA-00979: not a GROUP BY 表达式错误。如果我从视图中消除子查询(第 4 列),一切正常。任何想法将不胜感激!谢谢!!
select
l.LAB_GROUP,
l.NAME as LAB,
b.NAME as BENCH,
(select count(distinct s2.SAMPLE_NUMBER)
from SAMPLE s2 inner join TEST t2 on s2.SAMPLE_NUMBER = t2.SAMPLE_NUMBER and t2.STATUS in ('C', 'R') and s2.TEMPLATE <> 'QC_SAMPLE'
inner join LABORATORY_ENTRY le2 on t2.ANALYSIS = le2.ANALYSIS
where s2.LAB_GROUP = l.LAB_GROUP and le2.NAME = l.NAME and t2.X_BENCH = b.NAME and
((select count(t1.TEST_NUMBER)
from TEST t1
where t1.SAMPLE_NUMBER = t2.SAMPLE_NUMBER and t1.ANALYSIS = t2.ANALYSIS and t1.STATUS <> 'R') = 0)) as RFR
from LABORATORY l
inner join LABORATORY_ENTRY le on le.NAME = l.NAME
inner join X_BENCH b on b.NAME = le.X_BENCH
left join (SAMPLE s inner join TEST t on s.SAMPLE_NUMBER = t.SAMPLE_NUMBER and s.STATUS <> 'U'
and s.TEMPLATE <> 'QC_SAMPLE' and t.STATUS in ('I', 'P')) on t.ANALYSIS = le.ANALYSIS and s.LAB_GROUP = l.LAB_GROUP
left join V_LOC_DEPT_FAC ldf on ldf.LOCATION_NUMBER = s.STORAGE_LOC_NO
group by l.LAB_GROUP, l.NAME, b.NAME
【问题讨论】:
-
作为旁注,您可能需要考虑物化视图而不是视图,因为这看起来像一个昂贵的查询。
-
您似乎不需要
GROUP BY子句,因为您没有任何聚合函数作为选择的一部分;COUNT函数位于第 4 列的子查询中,而不是主子句的一部分。但是,如果您将这些子查询改为连接,这可能会更容易维护...... -
谢谢.. 计划是最终创建一个物化视图。
标签: oracle