PostgreSQL 将行动态转置为列

Question

您好，我试图让我的查询结果在每列 1 行中动态对齐，如果可能，请帮助我

例如这是我的桌子

id , names , comm    , contrib
1    samp1   randtext     9
2    samp1   randtext     2
3    samp1   randtext     3 
5    samp2   randtext     4 
6    samp2   randtext     1   

那么我试图得到的结果是

names  comm1    comm2    comm3    contrib1  contrib2  contrib3 
samp1  randtext,randtext,randtext    9      , 2       , 3
samp2  randtext,randtext,            4      , 1       ,  

感谢您的帮助。

Answer 1

我们可以将ROW_NUMBER 与数据透视查询结合使用：

WITH cte AS (
    SELECT *, ROW_NUMBER() OVER (PARTITION BY names ORDER BY id) rn
    FROM your_table
)

SELECT
    names,
    MAX(CASE WHEN rn = 1 THEN comm END) comm1,
    MAX(CASE WHEN rn = 2 THEN comm END) comm2,
    MAX(CASE WHEN rn = 3 THEN comm END) comm3,
    MAX(CASE WHEN rn = 1 THEN contrib END) contrib1,
    MAX(CASE WHEN rn = 2 THEN contrib END) contrib2,
    MAX(CASE WHEN rn = 3 THEN contrib END) contrib3
FROM cte
GROUP BY
    names
ORDER BY
    names;