【发布时间】:2021-01-13 14:56:02
【问题描述】:
我有这个过程,我们指定阶段文件的路径以及应该使用哪种文件格式,然后我们获取它的前 2 列并将其作为具有以下结构的类型数组的变体返回:
result = [
{ dim_label_name: 'Test1', dim_ona_name: 'Ona Test1' },
{ dim_label_name: 'Test2', dim_ona_name: 'Ona Test2' },
]
程序如下:
CREATE OR REPLACE PROCEDURE ADD_FIELD_AND_DIMENSION(FILE_FULL_PATH STRING, FILE_FORMAT_NAME STRING)
RETURNS VARIANT
LANGUAGE JAVASCRIPT
EXECUTE AS CALLER
AS
$$
var dimension_array = [];
try{
// Get the unique values of the available dimensions
var unique_dimension_query = "SELECT t.$1, t.$2 FROM "+FILE_FULL_PATH+"(FILE_FORMAT=>"+FILE_FORMAT_NAME+") t GROUP BY t.$1, t.$2";
var unique_dimension_stmt = snowflake.createStatement({sqlText: unique_dimension_query});
var rs = unique_dimension_stmt.execute();
var dimension_object = {};
while (rs.next()) {
dimension_object['dim_label_name'] += rs.getColumnValue(1);
dimension_object['dim_ona_name'] += rs.getColumnValue(2);
}
dimension_array.push(dimension_object);
return dimension_array;
}
catch(error) {
return error;
}
$$;
CALL ADD_FIELD_AND_DIMENSION('@ingest_stage_temp/my_file.csv', 'my_file_format');
返回的dimension_array 的结构只有一个对象的所有值都适合每个属性:
[
{ 'dim_label_name': 'Test1Test2Test3...', 'dim_ona_name': 'ONA Test1 ONA Test2 ONA Test3...' }
]
如何在 Snowflake 中将所有数据提取到拆分行中的对象数组中?
【问题讨论】:
标签: javascript sql stored-procedures snowflake-cloud-data-platform